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arsen [322]
3 years ago
12

A caterer needs to buy 21 pounds of pasta to cater a wedding. At a local store, 8 pounds of pasta cost $12. How much will the ca

terer pay for the pasta there
Mathematics
1 answer:
Zanzabum3 years ago
7 0

Answer:

31.5 $

Step-by-step explanation:

First lets se how much 1 pound of pasta costs in the store. We do this dividing the price for 8 pounds over those 8 pounds:

12/8 = $1.5 each pound

As 21 pounds are needed:

$1.5 * 21 = $31.5

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Given the function h(x) = x2 – 7x + 6, determine the average rate of change of
guapka [62]

Step-by-step explanation:

the average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

so,

(h(7) - (h(3)) / (7 - 3)

h(7) = 7² - 7×7 + 6 = 49 - 49 + 6 = 6

h(3) = 3² - 7×3 + 6 = 9 - 21 + 6 = -6

7 - 3 = 4

(6 - -6)/4 = 12/4 = 3

the average change rate in that interval is 3 (or fully 3/1).

4 0
3 years ago
Please any help with steps
Arada [10]
I think the answer is 1/2. C.
7 0
2 years ago
Read 2 more answers
A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student
umka2103 [35]

Answer:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X_{M}= 69.8 represent the mean for the age of grandmother

\bar X_{F}= 71.6 represent the mean for the age of grandfather

s_{M}= 8.38 represent the sample deviation for the age of grandmother

s_{F}= 6.65 represent the sample deviation for the age of grandfather

n_M = n_F= 10

Solution to the problem

For this case the confidence interval is given by:

(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n_M +n_F-2=10+10-2=18

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that t_{\alpha/2}=2.101

And replacing we got:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

5 0
3 years ago
How do I solve this finding the first four of the sequence?
nexus9112 [7]

Answer:

- 7, - 3, 1, 5

Step-by-step explanation:

Using the recursive rule and a₁ = - 7, then

a₂ = a₁ + 4 = - 7 + 4 = - 3

a₃ = a₂ + 4 = - 3 + 4 = 1

a₄ = a₃ + 4 = 1 + 4 = 5

The first four terms are - 7, - 3, 1, 5

4 0
3 years ago
A 72.9-foot rope from the top of a circus tent pole is anchored to the ground 44.9 feet from the bottom of the pole. What angle
Ilia_Sergeevich [38]

See the attachment.

It is in the attachment (photo)

4 0
3 years ago
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