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3 years ago

Part A

Mathematics

1 answer:

N76 [4]3 years ago

5 0

Step-by-step explanation:

Part A: We can write 40 + x + 25 = 180 because these angles are supplementary, meaning they add up to 180 degrees, and when we solve for x, we get x = 115°.

Part B: We can write y = x + 25 because these two angles are vertical angles, meaning they are equal and formed from the same lines. We know that x = 115°, so when we plug that in we get y = 140°.

Part C: z = 40° because these two angles are vertical angles. I hope this helps!

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A small rural town has experienced growth at a rate of 50 people per year since 2000. If the population of the town in 2000 was

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Population = 50x + 600

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Suppose the population of a town is 15,200 and is growing 2% each year. Write an equation to model the population growth. Predic

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1. So the current population of the town is 15 200 and is growing per year with 2%.
Find the population number after 10 years.
First, let’s find the value of 2% in decimal form
=> 2/100
=> 0.02

Now, let’s try to solve
Population = 15 200 ( 1 + (0.02 x 10) )
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3 years ago

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Ray does chores every day for a small allowance.he earns 1.50 a day for washing the dishes and x dollar a day taking out trash

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Answer:

Step-by-step explanation:

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3 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the zero-product property and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the second equation and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

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