<span>The answer is B. 72.25 percent.
The Hardy-Weinberg principle can be used:</span>
<em>p² + 2pq + q² = 1 </em>and <em>p + q = 1</em>
where <em>p</em> and <em>q</em> are the frequencies of the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq</em> are the frequencies of the genotypes.
<span>The <em>p</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15
To calculate the <em>P</em> allele frequency (<em>p</em>), the formula <em>p + q = 1</em> can be used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85
Knowing the frequency of the <em>P</em> allele (<em>p</em>), it is easy to determine the frequency of the <em>PP </em>genotype (<em>p²</em>):
p² = 0.85² = 0.7225
Expressed in percentage, p² = 72.25%.</span>
Answer:
Explanation:
Placoderms were the first jawed fish; their jaws likely evolved from the first of their gill arches. in spanish
placodermos
Answer: in the production systems of coal-burning power plants
The scenario will be Son: 25% colorblind daughter: 25% colorblind son: 25% of carrier daughters with normal vision: 25% normal son
<h3>What is color blindness?</h3>
The condition is frequently inherited. Certain eye diseases and medications are also possible causes. Men are more affected than women.
Color blindness is characterized by the inability to distinguish between red and green shades.
A colorblind man's genotype is XcY, and a heterozygous carrier female's genotype is XcX. A cross between XcY and XcX would result in progeny with the following ratio=
Son: 25% colorblind daughter: 25% colorblind son: 25% of carrier daughters with normal vision: 25% normal son.
Thus, the couple is likely to have a son who is half normal and half affected. Similarly, the couple is likely to have 50% normal daughters and 50% colorblind daughters.
For more details regarding color blindness, visit:
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