All categories

3 years ago

Find the next three terms in this sequence: 5120, 1280, 320, 80, ...

Mathematics

1 answer:

dimaraw [331]3 years ago

8 0

This seems to be dividing by 4, so the next numbers are 20, and then 5. If there is a 3rd, it's 1.25

You might be interested in

What is 1/5 × -3/2 +4/5 × -2/7 × -1/6 × -2/7

velikii [3]

Answer:

$\frac{-457}{1470}$

Step-by-step explanation:

$\frac{1}{5} \times \frac{-3}{2} + \frac{4}{5} \times \frac{-2}{7} \times \frac{-1}{6} \times \frac{-2}{7}$

$(\frac{1}{5} \times \frac{-3}{2}) + (\frac{4}{5} \times \frac{-2}{7} \times \frac{-1}{6} \times \frac{-2}{7})$

$\frac{-3}{10} +\frac{-16}{1470}$

$=\frac{-457}{1470}$

4 0

3 years ago

Read 2 more answers

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they double the

valina [46]

Answer:

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third week = 109 times 2= 218

Step-by-step explanation:

Let x be the number of boxes sold in first week

the girls sold 5 more boxes the second week

So number of boxes sold in second week is x+5

they double the sales of the second week for the third week

So number of boxes sold in third week is 2 (x+5)

Total boxes sold is 431

$x+x+5+2(x+5)=431$

$x+x+5+2x+10=431$

$4x+15=431$

subtract 15 from both sides

$4x=416$

divide by 4 on both sides

$x=104$

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third week = 104 times 2= 218

4 0

3 years ago

Line RS bisects PQ at point R, Find RQ if PQ = 14 cm

Dovator [93]

If PQ is 14, each segment, PR and RQ will be 7.
14 = PR + 7.

6 0

3 years ago

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

Find out the distance BC

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

Find out the distance AB

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

Find out the area

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

3 years ago

10-1: Compound Probability

ahrayia [7]

Answer:

Step-by-step explanation:

Probability of black pens = 3/14

Probability of white paper clips = 16/40

to find the probability of black pen and white paper clip we have to multiply these two probability.

3/14 x 16/40 = 48/560 = 8.6

3 0

3 years ago