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Lostsunrise [7]
3 years ago
10

A certain television is advertised as a 58-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches t

all is the TV?
Mathematics
2 answers:
ra1l [238]3 years ago
6 0

Your answer will be 16

a_sh-v [17]3 years ago
6 0

Answer:

The height of the television is:

  • <u>40 inches</u>.

Step-by-step explanation:

To solve the proposed exercise you must understand two things:

  1. Since the flat figure of a television is a rectangle, it can be subdivided into a right triangle (since it has at least a 90 ° angle)
  2. A variation of the Pythagorean Triangle will be used.

The Pythagorean triangle tells us that the sum of the base squared and the height squared of a right triangle will be equal to the hypotenuse (diagonal) squared of the triangle, which is usually expressed like this:

  • a^2 + b^2 = c^2

But to make it more understandable, let's express it like this:

  • base^2 + height^2 = diagonal^2

Since the diagonal and the base (width) of the television are provided in the exercise, we must clear the height and calculate:

  • height^2 = diagonal^2 - base^2
  • height^2 = 58^2 - 42^2
  • height^2 = 1600

To identify the value if in the square, you must apply square root to the obtained value:

  • height^2 = square root of 1600
  • <u>height^2 = 40 inches</u>.
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Find a unit vector in the same direction as the given vector: v = −14.5i + 2.5 j.
Elis [28]

ANSWER

-  \frac{29}{866}  \sqrt{866} i + \frac{5}{866}  \sqrt{866} j

EXPLANATION

The given vector is v = −14.5i + 2.5 j.

The magnitude of this vector is

|v|  =  \sqrt{ {( - 14.5)}^{2}  +  {2.5}^{2} }

v|  =  \sqrt{ {( - 14.5)}^{2}  +  {2.5}^{2} }

v|  =  \sqrt{ 216.5}  =  \frac{ \sqrt{866} }{2}

The unit vector in the direction of this vector is

=  \frac{v}{ |v| }

= -   \frac{14.5}{ \frac{ \sqrt{866} }{2} } i +    \frac{2.5}{ \frac{ \sqrt{866} }{2} } j

=  -  \frac{29}{866}  \sqrt{866} i + \frac{5}{866}  \sqrt{866} j

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3 years ago
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MatroZZZ [7]
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