Answer:
See below
Step-by-step explanation:
![x = \frac{1}{2} \times \sqrt{6} \\ \\ x = \frac{ \sqrt{6} }{2} \\ \\ y = \frac{ \sqrt{3} }{2} \times \sqrt{6} \\ \\ y = \frac{ \sqrt{3 \times 6} }{2} \\ \\ y = \frac{ \sqrt{18} }{2} \\ \\ y = \frac{ 3\sqrt{2} }{2}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%20%5Csqrt%7B6%7D%20%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B6%7D%20%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%7D%7B2%7D%20%20%5Ctimes%20%20%5Csqrt%7B6%7D%20%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B3%20%5Ctimes%206%7D%20%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B18%7D%20%7D%7B2%7D%20%20%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B%203%5Csqrt%7B2%7D%20%7D%7B2%7D%20%20)
Therefore the answer is D. (x + 1)(x2 + 2)
Answer:
5040,56
Step-by-step explanation:
We have to construct pass words of 4 digits
a) None of the digits can be repeated
We have total digits as 0 to 9.
4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)
No of passwords = 10P4
= ![10(9)(8)(7)\\=5040](https://tex.z-dn.net/?f=10%289%29%288%29%287%29%5C%5C%3D5040)
b) start with 5 and end in even digit
Here we restrain the choices by putting conditions
I digit is compulsorily 5 and hence only one way
Last digit can be any one of 0,2,4,6,8 hence 5 ways
Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)
=56
all
150+67=217 woohoo it's 217 not 2000 sooo him and all boxes
Answer:
PLEASE BRAINLIEST
Step-by-step explanation:
400-2a =332
400-332 =2a
2a=68
a=34