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gizmo_the_mogwai [7]
3 years ago
9

Simplify the expression: (1 + 4t)(3) =

Mathematics
2 answers:
harina [27]3 years ago
7 0
I think its  3x1+3x4t=3+12t
VikaD [51]3 years ago
4 0
Multiply it out. 3*1+3*4t=3+12t
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El área de un rectángulo es 675cm2, si el largo es 3 veces. ¿Cuáles son las dimensiones del rectángulo?
Gala2k [10]
The answer is 15 cm. Hope I could be of help! ; )
7 0
3 years ago
What is the scale factor for pre-image IJKH to image MNOL?
solniwko [45]

Answer:

Step-by-step explanation:

Given are two rectangles MNOL and IJKH

MNOL is the image and IJKH is the preimage.

OBviously similarity is preserved between these.

Hence sides will be proportional

i.e. l1/l2 = w1/w2 = Scale factor k

This can also be written as

Scale factor square = k^2=\sqrt{ \frac{areaI}{area2} }

Scale factor = square root of ratio of rectangle areas

Find ratio as

\frac{375}{135} =\frac{25}{9}

k = Scale factor = square root of the above fraction

=\frac{5}{3}

5 0
4 years ago
I NEED HELP
denpristay [2]
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7 0
3 years ago
Read 2 more answers
Help center of circle
Lelu [443]

Answer:

Center = (7, - 5)

Radius = 3

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  + 14x - 10y + 65 = 0 \\  {x}^{2}  + 14x +  {y}^{2}  - 10 + 65 = 0 \\ ( {x}^{2}  + 14x +  {7}^{2})  -  {7}^{2}  +  ({y}^{2}  - 10y +  {5}^{2})  \\-  {5}^{2}  + 65 = 0 \\ (x + 7)^{2}  + (y - 5)^{2}  - 49 - 25 + 65 = 0 \\  (x + 7)^{2}  + (y - 5)^{2}  - 49  + 40= 0 \\   (x + 7)^{2}  + (y - 5)^{2}  - 9= 0 \\   (x + 7)^{2}  + (y - 5)^{2}   =  9 \\  (x + 7)^{2}  + (y - 5)^{2}   =   {3}^{2}  \\  equating \: it \: with \: \\ (x  -  h)^{2}  + (y - k)^{2}   =   {r}^{2}  \\  - h = 7 \implies \: h =  - 7 \\  - k =  - 5 \implies \: k = 5 \\ center = ( - h, \:  - k)  = (7, \:  \:  - 5) \\  \\ radius \: r = 3

7 0
3 years ago
Find the value of x in the triangle shown below.<br> 4<br> 7.2<br> 7.2<br> 32
vladimir1956 [14]

Answer: 74

Step-by-step explanation:

It’s an isosceles triangle so both angles are equal so if one angle is 32. Do 180-32 then divide your answer by 2 =74

5 0
3 years ago
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