Answer:
12c + 14d - 4
Step-by-step explanation:
16d + 20c + 5d -7 - 8c - 7d + 3
Simplify the expression
__________________________
To solve, we need to first take in mind the fact that there are different like terms within this expression. Like terms are numbers or values that end in different symbols, such as variables or exponents. Since we are filled with variables such as c and d. We can do as followed :
Combine the "d" like terms :
16d + 5d - 7d
21d - 7d
14d
Combine the "c" like terms :
20c - 8c
12c
Combine the constants :
-7 + 3
-4
Now add all of the values together to get the final expression.
12c + 14d - 4
Answer:
(a) 498501
(b) 251001
Step-by-step explanation:
According Gauss's approach, the sum of a series is
.... (1)
where, n is number of terms.
(a)
The given series is
1+2+3+4+...+998
here,
Substitute , and in equation (1).
Therefore the sum of series is 498501.
(b)
The given series is
1+3+5+7+...+ 1001
The given series is the sum of dd natural numbers.
In 1001 natural numbers 500 are even numbers and 501 are odd number because alternative numbers are even.
Substitute , and in equation (1).
Therefore the sum of series is 251001.
Answer:
−49x8−3x−4
Step-by-step explanation:
−3x−4−49x7x
=−3x+−4+−49x8
hope this helps
Answer:
here you goes hope it helps you
Step-by-step explanation:
1
Common factor
−
3
2
+
7
+
2
0
-3y^{2}+7y+20
−3y2+7y+20
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}-7y-20)
−1(3y2−7y−20)
2
Use the sum-product pattern
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}{\color{#c92786}{-7y}}-20)
−1(3y2−7y−20)
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)
−1(3y2+5y−12y−20)
3
Common factor from the two pairs
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+5y-12y-20)
−1(3y2+5y−12y−20)
−
1
(
(
3
+
5
)
−
4
(
3
+
5
)
)
-1(y(3y+5)-4(3y+5))
−1(y(3y+5)−4(3y+5))
4
Rewrite in factored form
Solution
−
1
(
−
4
)
(
3
+
5
)
