The answer for your question is 45 cm long
Let
denote the value on the
-th drawn ball. We want to find the expectation of
, which by linearity of expectation is
![E[S]=E\left[\displaystyle\sum_{i=1}^5B_i\right]=\sum_{i=1}^5E[B_i]](https://tex.z-dn.net/?f=E%5BS%5D%3DE%5Cleft%5B%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E5B_i%5Cright%5D%3D%5Csum_%7Bi%3D1%7D%5E5E%5BB_i%5D)
(which is true regardless of whether the
are independent!)
At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.

and so
![E[X_i]=\displaystyle\sum_{i=1}^{10}x\,P(X_i=x)=\frac1{10}\frac{10(10+1)}2=5.5](https://tex.z-dn.net/?f=E%5BX_i%5D%3D%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E%7B10%7Dx%5C%2CP%28X_i%3Dx%29%3D%5Cfrac1%7B10%7D%5Cfrac%7B10%2810%2B1%29%7D2%3D5.5)
Then the expected value of the total is
![E[S]=5(5.5)=\boxed{27.5}](https://tex.z-dn.net/?f=E%5BS%5D%3D5%285.5%29%3D%5Cboxed%7B27.5%7D)
Hello There!
To find the mean, add up all the numbers and divide according to how many numbers there are. The mean for this set would be <em>"9"</em>
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To find the median, place the numbers in value order and find the middle. if there is no middle, add up the two numbers in middle and divide by 2. In this set, the median would be <em>"8.5"</em>
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To find the mode or modal value, it is best to put the numbers in order. Then count how many of each number. A number that appears most often is the mode. In this set, there would be no mode.
The range of a set of data is the difference between the highest and lowest values in the set. In this set, the range would be <em>"12"</em>
Area of cone = 1/3 base × height = 1/3 × 8 × 10 = approximately 26.7 m
Ans= approx. 26.4 m
Happy to help. Please mark as brainliest!