(a)
the list would be
-20, -12, -8, -1, 1, 5, 10
the other intergers would have to be greater than 1 in order to be on the correct side and cause 1 to be in the middle. They could be anything but 5 and 10 because these were already chosen.
(b)
the list would be like before
-3 was not included so one of the chosen would be -3 and the other would have to be less than -3 but not -8, -12, or -20 beacuse those were already chosen
5x-4=4x+8
-4x. -4x
X-4=8
+4. +4
X=12
5(12)-4=4(12)+8
60-4=48+8
56=56
You can just do 1x30 which equals 30
210/360 = 7/12, meaning the shaded area is 7/12 of the entire circle.
The circle has radius 12 in, so its total area is π (12 in)^2 = 144π in^2.
Then the area of the shaded region is 7/12 of this, or
7/12 * (144 π in^2) = 84π in^2 ≈ 263.89 in^2
