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Dimas [21]
3 years ago
9

A group of seven adults went to the movies. The total cost of the movie tickets was $30. This doesn't seem possible, does it? Af

ter all, 30 is not evenly divisible by 7. Ah, but there's a hitch. The reason that $30 was the total cost was that some members of the group were senior citizens, so they got to see the movie at half price. How many of the group were senior citizens, and how much did the tickets cost?
Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

no. of senior citizens=x

no.of other people=7-x

cost=30=k(7-x)+(k/2)x. k is the cost of a ticket

k(7-x+x/2)

k(7-x/2)-30=0

k=60/(14-x)

now do trial and error substitution for (x<7) until u get a whole number for k also (k<30). if you have the skills you can suggest the number yourself

ie x= 2, k=5$

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EleoNora [17]

Answer:

  •   <u> 7,692 moose.</u>

Explanation:

The table that shows the pattern for this question is:

Time (year) Population

  0                   40

  1                     62

  2                    96

  3                   149

  4                   231

A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.

Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.

Thus you must find both P₀ and r.

<u>1) P₀ </u>

  Using the first term of the sequence (0, 40) you get:

   P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀

Then, P₀ = 40

<u>  2) r</u>

Take two consecutive terms of the sequence:

  • P(0) = 40 r⁰ = 40
  • P(1) = 40 r¹ = 40r = 62
  • P(1) / P(0) = 40r / 40 = 62/40
  • r = 62/40 = 1.55

 

You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55

<u>3) Model</u>

 

Thus, your model is P(x) = 40(1.55)ˣ

<u> 4) Population of moose after 12 years</u>

  • P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.
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<span>9x-6y=3
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Answer:

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