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julia-pushkina [17]
4 years ago
10

How to solve this one

Mathematics
2 answers:
brilliants [131]4 years ago
8 0
If the blue piece is half of the length of green, which is 12, then the blue piece would be 6cm long. 12 + 6 would represent the total length of both pieces, which is 18.
ASHA 777 [7]4 years ago
3 0
<h2><u><em>Answer:</em></u><em> 18 cm</em></h2>

Step-by-step explanation:

The question is essentially asking us to divide 12 by 2 and then add the quotient to the length of the green ribbon. Let me explain:

The green ribbon is 12 cm long. The question tells us that the blue piece is half the length of the green one. Well, what's half of 12? 6! So...

Green ribbon: 12 cm

Blue ribbon: 6 cm

To find what the total length of both the ribbons is, we just need to add the lengths together.

12 + 6 = 18 cm

<em>Hope this was helpful! let me know if you have any further questions. :)</em>

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Isolate x by adding 8 to both sides.
3 = x/3
Then, multiply by 3 on both sides.
9 = x
To prove that this is right, you can imput 9 into the equation and it equals -5.
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The table below shows the number of advanced degrees (in thousands) earned in the U.S. during a recent year by gender and type o
Elden [556K]
May I leave you to simplify the following values of probability?
(a) 512/1906.
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8 0
4 years ago
Can you please help me with this one please
son4ous [18]
The volume of this box is indeed 84 in^3.  What were you looking for beyond that?

Base:  (7 in)(3 in) = 21 in^2
Height:  4 in
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5 0
4 years ago
Read 2 more answers
Helppp please show work
Mamont248 [21]

Step-by-step explanation:

<u>Given</u><u> </u><u>that</u><u>:</u><u>-</u>

  • Side AC measures 6 units
  • Side BC measures 9.5 units
  • Side AB measures 11 units

<u>To</u><u> </u><u>find</u><u>:</u><u>-</u>

  • The cosB as a decimal rounded to the nearest hundredth

<u>We</u><u> </u><u>know</u><u> </u><u>that</u><u>, </u>

{ \bigstar \: { \underline{ \boxed{ \cos( \theta ) \:  =  \sf\frac{adjecent \: side}{hypotenuse}  }}}}

<u>Solution</u><u>:</u>

\longrightarrow \rm  \cos(B)  =  \dfrac{BC}{AB}

\longrightarrow \rm  \cos(B)  =  \dfrac{9.5}{11}

\longrightarrow \rm  \cos(B)  =  \dfrac{95}{110}

\longrightarrow \rm  \cos(B)  =  0.8 63

\longrightarrow  \rm  \cos(B)   \approx \: 0.9

<u>Therefore:</u>

  • Cos B equals 0.9

6 0
2 years ago
We are going to fence in a rectangular field that encloses 200m2. If the cost of thematerial for of one pair of parallel sides i
Crazy boy [7]

Answer:

x = y \approx 14.142\,m

Step-by-step explanation:

Let be x and y the length and width of the rectangular field, whose area and perimeter are, respectively:

A = x\cdot y

p = 2\cdot (x + y)

Building cost is minimum when perimeter is minimum, then equation system must be reduced and critical values have to be found:

x \cdot y = 200

p = 2\cdot (x + y)

Then,

y = \frac{200}{x}

p = 2\cdot \left(x + \frac{200}{x} \right)

Now, critical values are determined by First and Second Derivative Tests:

FDT

p' = 2 \cdot \left(1 -\frac{200}{x^{2}}\right)

2\cdot \left(1-\frac{200}{x^{2}} \right) = 0

x^{2} - 200 = 0

x = \sqrt{200}

x \approx 14.142\,m (As length is a positive number)

SDT

p'' = 2\cdot \left(\frac{400}{x^{3}} \right)

p'' = 0.283 (which means that critical point leads to a minimum).

Now, the value of the other variable is:

y = \frac{200\,m^{2}}{14.142\,m}

y = 14.142\,m

Lastly, the cost of building the fence is:

C = 2 \cdot [\$ 3 + \$ 8 ]\cdot (14.142\,m)

C = \$ 311.124

5 0
3 years ago
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