F’(x)= -akxsinkx
F’’(x)= -a(kx)^2coskx
I’m really sorry if the answer turned out wrong but I tried my best!
Let ‘s’ be the son’s age 12 years ago.
Let ‘f’ be the father’s current age.
4 years ago, the son was:
s-4
So, his father is currently:
3(s-4)
=
3s-12
Therefore:
f = 3s-12
In twelve years, the son will be:
s+12
And the father will be:
f+12
This can also be written as:
3s-12+12 as the fathers younger age would be f = 3s+12
=
3s
So, we know that s+12 is half the fathers current age, meaning the father is currently 2(s+12) which is equivalent to 2s+24. Also, we know that the father is currently 3 times the sons age 12 years ago, so 3s (proven by the calculations we made above). Therefore, 2s+24=3s which means 24=s. We can then substitute this, and we will receive 24+12 = 36
Son’s current age: 36
We then substitute the son’s age 12 years ago into 2s+24 to give us the father’s age.
2(24)+24 = 72
Father’s current age: 72
Answer:
The first term is 42.
Step-by-step explanation:
The common difference is 142 - 140 = 2 so we have
50th term = a1 + 2(50 -1) = 140 where a1 is the first term
a1 + 98 = 140
a1 = 140 - 98 = 42.
I’m so sorry I need points but I’m gonna manifest that someone smarter will see this and answer
Answer:
1: 18.75
Step-by-step explanation:
We multiply both sides by 5.
