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Sergeu [11.5K]
3 years ago
15

10

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

5/14

Step-by-step explanation:

5 + 9 = 14- so our denominator is 14

Theres 5 milk chocolates, so the probability is 5/14

I hope this helped, please mark Brainliest, thank you !!

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Step-by-step explanation:

y -4x = -1

y = 4x -1

then y = Mx + b

m = 4

b = -1

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Which of the following inequalities is not true?
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| - 9|  =  |9|

This is because modulus number will be always positive

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HAVE A GOOD DAY!

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Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX ​ is translated 4 units right and 3 uni
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Okay, so first of all, if the trapezoid was translated right 4,
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3 years ago
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What is the GCF of 8,12,16
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3 years ago
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A researcher computes the following 2 x 3 between-subjects ANOVA, in which 11 participants were observed in each group. Which ef
pishuonlain [190]

Answer:

D. There were no significant effects.

Step-by-step explanation:

The table below shows the representation of the significance level using the two-way between subjects ANOVA.

Source of Variation            SS          df          MS          F                P-value

Factor A                             10          1              10           0.21           0.660

Factor B                             50         2             25          0.52          0.6235  

     

A × B                                  40          2             20         0.42           0.6783

Error                                   240        5             48           -               -

Total                                   340       10             -             -                  -

From the table above , the SS(B) is determined as follows:

SS(B) = SS(Total)-SS(Error-(A×B)-A)

         =  340-(240-40-10)

         = 50

A researcher computes the following 2 x 3 between-subjects ANOVA;

k=2

n=3

N(total) = no of participants observed in each group =11

df for Factor A= (k-1)

=(2-1)

=1

df for Factor B = (n-1)

=(3-1)

=2

df for A × B    

 = 2 × 1

 = 2

df  factor for total

=(N-1)

=11-1

=10

MS = SS/df

Thus, from the table, the P-Value for all data is greater than 0.05, therefore we fail to reject H₀.

4 0
3 years ago
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