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3 years ago

Someone please help with this math question, it is not hard if you're good at math, but I'm on a test.

Mathematics

1 answer:

notsponge [240]3 years ago

5 0

Answer:

Step-by-step explanation:

Midpoint means EF and FG are both 8 the whole thing is 19 so 19 - 16 = 3

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A minor league hockey team had the following scores for the start of the season for the start of the season 3,6,2,1,2,3,0,4,5,1,

PolarNik [594]

ANSWER

The mean will be the most affected.

EXPLANATION

Given;

$3,6,2,1,2,3,0,4,5,1,5,4$

Initially, the mean, median and mode is calculated thus;

$\begin{gathered} mean=\frac{3+6+2+1+2+3+0+4+5+1+5+4}{12} \\ =\frac{36}{12} \\ =3 \\ mode=1,2,3,5 \end{gathered}$

To calculate the median, we need to re-arrange in ascending order. Hence;

$\begin{gathered} 0,1,1,2,2,3,3,4,4,5,5,6. \\ median=\frac{(3+3)}{2} \\ =\frac{6}{2}=3 \end{gathered}$

After adding 9;

The new data is;

$0,1,1,2,2,3,3,4,4,5,5,6,9$

The new mean is;

$\begin{gathered} mean=\frac{3+6+2+1+2+3+0+4+5+1+5+4+9}{13} \\ =3.46 \\ Mode=3 \\ median=3 \end{gathered}$

The mean will be the most affected.

4 0

1 year ago

Three times a number increased by 8 is no more than the number 4 find the number

loris [4]

The answer is less than or equal to -4. Because -4+8=4

3 0

3 years ago

X+ 2y=3 and x=5 in y=mx+b form

lesya692 [45]

I don’t know how to solve those type of problems sorry

6 0

3 years ago

pleaseeee help please for f(x) = x2 and g(x) = (x − 3)2, in which direction and by how many units should f(x) be shifted to obta

wariber [46]

F(x) should be shifted right 3 units.

4 0

3 years ago

Read 2 more answers

Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq

Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

$\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9$

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

$125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9$

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0

3 years ago