A line passes (-8,-2) and has a slope of 5/4. Write an equation in Ax + By=C
2 answers:
Answer:
5x-4y = -32
Step-by-step explanation:
First write the equation in point slope form
y-y1 = m(x-x1)
y - -2 = 5/4 ( x- -8)
y+2 = 5/4 (x+8)
Multiply each side by 4 to clear the fraction
4( y+2 )= 4*5/4 (x+8)
4y +8 = 5(x+8)
4y+8 = 5x+40
Subtract 4y from each side
8 = 5x-4y +40
Subtract 40 from each side
-32 = 5x-4y
5x-4y = -32
Answer:
The answer is
<h2>5x - 4y = -32</h2>
Step-by-step explanation:
To write an equation of a line given a point and slope use the formula
y - y1 = m( x - x1)
where
m is the slope
( x1 , y1) is the point
From the question
slope = 5/4
point (-8 , -2)
So the equation of the line is
<h2>

</h2>
Multiply through by 4
4y + 8 = 5( x + 8)
4y + 8 = 5x + 40
5x - 4y = 8 - 40
We have the final answer as
<h3>5x - 4y = -32</h3>
Hope this helps you
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Hope this helps ^-^