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Illusion [34]
3 years ago
8

A line passes (-8,-2) and has a slope of 5/4. Write an equation in Ax + By=C

Mathematics
2 answers:
klemol [59]3 years ago
6 0

Answer:

5x-4y = -32

Step-by-step explanation:

First write the equation in point slope form

y-y1 = m(x-x1)

y - -2 = 5/4 ( x- -8)

y+2 = 5/4 (x+8)

Multiply each side by 4 to clear the fraction

4( y+2 )= 4*5/4 (x+8)

4y +8 = 5(x+8)

4y+8 = 5x+40

Subtract 4y from each side

8 = 5x-4y +40

Subtract 40 from each side

-32 = 5x-4y

5x-4y = -32

liubo4ka [24]3 years ago
6 0

Answer:

The answer is

<h2>5x - 4y = -32</h2>

Step-by-step explanation:

To write an equation of a line given a point and slope use the formula

y - y1 = m( x - x1)

where

m is the slope

( x1 , y1) is the point

From the question

slope = 5/4

point (-8 , -2)

So the equation of the line is

<h2>y + 2 =  \frac{5}{4} (x + 8)</h2>

Multiply through by 4

4y + 8 = 5( x + 8)

4y + 8 = 5x + 40

5x - 4y = 8 - 40

We have the final answer as

<h3>5x - 4y = -32</h3>

Hope this helps you

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The equation of line perpendicular to 4y = x-8 passing through (3,-3) is:

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Step-by-step explanation:

Given equation of line is:

4y=x-8

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The equation of line perpendicular to 4y = x-8 passing through (3,-3) is:

y = -4x+9

Keywords: Equation of line, slope

Learn more about equation of line at:

  • brainly.com/question/4837736
  • brainly.com/question/4805611

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