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3 years ago

Which is an irrational number

Mathematics

1 answer:

Rufina [12.5K]3 years ago

7 0

Answer:

An irrational number is any number than cannot be written in the form p/q, where q is 0 Ex. pi, non-perfect squares

Step-by-step explanation:

In this case D. isn't rational but is irrational

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a 5 inch tall bamboo shoots double in height every 3 days if the equation equals y=ab^x where x is a number of doubling periods

alekssr [168]

A = initial amount, which is 5 inches

b = rate of increasing, in this case 200% or 2.0 (it's being doubled its height, so the rate would be twice as much as its full state)

Hope this helped!

4 0

3 years ago

1. A right angled triangle has two shorter sides and one is twice as long as the other. The hypotenuse is 25 cm long. What are t

Semenov [28]

Step-by-step explanation:

The hypotenuse of a right-angled triangle = 25 cm

One side is twice as long as the other.

Let the other side is x.

First side = 2x

Using Pythagoras theorem to find the lengths of the shorter sides.

$x^2+(2x)^2=25^2\\\\x^2+4x^2=625\\\\5x^2=625\\\\x^2=125\\\\x=11.18\ cm$

So, the other side = 11.18 cm

First side = 2(11.18) = 22.36 cm

So, the lengths of the shorter sides are 11.18 cm and 22.36 cm.

7 0

3 years ago

What is the value of 2 in the number 346,578.29

Gwar [14]

The 2 is in the tenths place so it is two-tenths.

Two-tenths = 2/10= .2

I hope that answers your question.

7 0

3 years ago

Read 2 more answers

The product of two integers is eighty,their quotient is five.Write both integers in numerical order and separated by a comma,no

Goryan [66]

SOLUTION

Let the two integers be x and y.

Now, the product of x and y, is 80, that is

$\begin{gathered} x\times y=80 \\ xy=80\ldots\ldots\text{.equation 1} \end{gathered}$

The quotient of x and y is 5, that is

$\begin{gathered} x\div y=5 \\ \frac{x}{y}=5\ldots\ldots\ldots\ldots\text{.}\mathrm{}\text{equation 2} \end{gathered}$

From equation 2, make x, the subject, we have

$\begin{gathered} \frac{x}{y}=5 \\ \text{cross multiplying } \\ 5\times y=x \\ x=5y \end{gathered}$

Now substitute the x for 5y into equation 1, we have

$\begin{gathered} xy=80 \\ 5y\times y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=\frac{80}{5} \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}$

Now substitute y for 4 into any of the equations.

Let us use equation 1 again, we have

$\begin{gathered} xy=80 \\ x\times4=80 \\ 4x=80 \\ x=\frac{80}{4} \\ x=20 \end{gathered}$

Hence the answer is 4, 20

4 0

1 year ago

Como se llama estos signos < y >

Tresset [83]

Answer:

<em>greater than and less than</em>

<em>mayor que y menor que</em>

4 0

3 years ago