The first finger on the left (Index) is choice "2" (1,Q,A,Z)
The second finger on the right (Middle) is choice "4" (8,I,K)
The first finger on the right (Index) is "3" (7,U,J,M
Which leaves choice "1" (3,E,D,C)
Hope this helps
Answer:
The history of agriculture in the United States covers the period from the first English settlers to the present day. In Colonial America, agriculture was the primary livelihood for 90% of the population, and most towns were shipping points for the export of agricultural products. Most farms were geared toward subsistence production for family use. The rapid growth of population and the expansion of the frontier opened up large numbers of new farms, and clearing the land was a major preoccupation of farmers. After 1800, cotton became the chief crop in southern plantations, and the chief American export. After 1840, industrialization and urbanization opened up lucrative domestic markets. The number of farms grew from 1.4 million in 1850, to 4.0 million in 1880, and 6.4 million in 1910; then started to fall, dropping to 5.6 million in 1950 and 2.2 million in 2008
Explanation:
Answer:
Correct option is
A. She can add a digitizer over the screen on her laptop
Explanation:
A digitizer is a hardware that receives analogue signal and converts is to digital signal.To use stylus on a normal laptop when can attach a digitizer to the laptop.These digitizer comes in form of Tablet (Graphics Tablet)
Graphics tablet is an external tablet like slate with a dedicated stylus for hand drawn designing and arts. Use of stylus gives more command over design features.It can read any kind of hand written data and transfer to PC.
Answer:
The code to this question as follows:
Code:
if(x < y) //if block that check value of x less then value of y
{
if(x<z) // inner if block that check value of x less then value of z
{
min = x; //assign value of x in min variable
}
else // inner else block when condition is false
{
min = z; //assign value of z in min variable
}
}
else //outer else block
{
if(y<z) //if block to check value of variable y is less then value of z
{
min = y; //assign value of y in min variable
}
else //else block
{
min = z; //assign value of z in min variable
}
}
Explanation:
In the given question it is defined, that an integer variable " x, y,z, and min" is declared, in which variable "x,y, and z" value is defined, and the variable is used to assign a big value.
- To check the biggest value we use the if-else statement in which, and if block check value of x is less than then the value of y if this condition is true so, inside this another if block declares, that will check if the value of x is less then z. if this is true, it will assign the value of x in min variable else it will assign the value of z in min.
- In the outer else part, another conditional block has used, that checks if the value of y is less than then the value of z if it is true, it assigns the value of y in min else it will assign the value of z in min.
Answer:
Explanation:
Let G denote an unambiguous Grammar capable of producing simple mathematical expressions, involving operators +,-,*,/. These operators are left associative (which ensures left to right evaluation). S is the start symbol of the Grammar i.e. the production starts from S. n denotes a number and is a terminal i.e. we can't produce anything further from n. Then, the solution is as follows :
S → S + T |S - T | S
T→T | F | T*F|F
F → n
Here, S, T and F are variables. Note that /,* have been given precedence over +,-.
