Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer:
Samuel slept for 1/4 of the distance.
Step-by-step explanation:
The information provided are:
- Samuel fell asleep halfway home.
- He didn't wake up until he still had half as far to go as he had already
- gone while asleep.
Consider that the total distance covered was 1.
Then from the first point we know that Samuel fell asleep after covering a distance of 1/2.
It is provided that he woke up only after covering half of the remaining distance.
That is, he slept for 1/4 of the remaining distance.
Thus, Samuel was asleep for 1/4th of the entire trip home.
Answer:
C. 5 Shirts for $21
Step-by-step explanation:
I conclude this when I calculate the amount of money needed for a singular shirt in every "bundle" by using division.
First I calculated how much you'd have to pay for one shirt in the six-pack collection fo shirts, and I resulted in $4.25 for each shirt. The problem in number form is: 25.50÷6=4.24. By dividing the total with six you result in the singular price of the individual price of each shirt in the pack.
As for the other packs, my calculations resulted in $4.50 for the 4 shirts pack and $4.20 for the 5shirts pack.
Unit Rate is the Constant Ratio
Answer:
what's the context of this?