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Olenka [21]
3 years ago
13

The following dot plot represents a random sample of elementary students and the number of children that live in their home.

Mathematics
1 answer:
NISA [10]3 years ago
7 0

1.

None of the households in the United States contain five children.

2.

The majority of the households in the United States, with at least one child, contain less than three children.

If thats wrong dont go off on me

~s9154499~

~Mia for short~

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x^2

Step-by-step explanation:

x > 0~\text{means that x is positive number.}

\text{Square of both negative and positive numbers are always positive.}\\\\\text{So,}~ x^2~\textbf{is positive.}

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If JM = 5x – 8 and LM = 2x - 6, which expression represents JL?
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Step-by-step explanation:

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What is the area of a rectangle with length 12 meters and width 6 meters?
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3 years ago
A consumer survey indicates that the average household spendsμ= $185on groceries each week. The distribution of spending amounts
Vitek1552 [10]

Answer:

P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>0.6)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the average household spent of a population, and for this case we know the distribution for X is given by:

X \sim N(185,25)  

Where \mu=185 and \sigma=25

We are interested on this probability

P(X>200)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>0.6)=1-P(z

7 0
3 years ago
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