Answer:
Therefore the ball strikes the ground 5.98 s after kick.
Step-by-step explanation:
Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation 
where h is height in feet and t is time in second.
When the ball touches the ground then the height will be zero.
i.e h(t)=0
Therefore
Since -2≠0 then 
[The solution of a quadratic equation ax²+bx+c=0 is
here a=8, b=-32 and c=-95]
![\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}](https://tex.z-dn.net/?f=%5CRightarrow%20t%20%3D%5Cfrac%7B-%28-32%29%5Cpm%5Csqrt%7B%28-32%29%5E2-%5B4%5Ctimes8%5Ctimes%28-95%29%5D%7D%20%7D%7B2%5Ctimes8%7D)
Therefore t= 5.98 or -1.98
since time can not be negative So , t=5.98 s
Therefore the ball strikes the ground 5.98 s after kick.
Answer:
Hope the below answer is easy to understand
Step-by-step explanation:
1) Given the four angles of a quadrilateral are in the ratio 1:2:3:4
Then Let the angles are x,2x,3x and 4x
We know that total of four angles of a quadrilateral =360 °
∴x+2x+3x+4x=360 °
⇒10x=360 °
⇒x=36 °
hence the measures of angles are 36 ° ,72 ° ,108 ° ,144 °
2) Measure of interior angle of a polygon= 180°.
Sides of the polygon = 7 sides
Therefore,
Interior angle of the polygon having 7 sides = 180/7 = 25 5⁄7°
Five hundred and eight thousand three hundred and seventy two
You have to put the problem down we cant help you if its not there
sorry but please put equation in or problem
