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salantis [7]
3 years ago
12

Brady dropped a bouncy ball from a height of 64 feet. After the second bounce, the ball reached a height of 36 feet. write a rul

e to represent the height of the ball after each bounce, then find the height after the fourth bounce
Mathematics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

Height  = 20.248 ft

Step-by-step explanation:

We can model this process with an exponential function

Height = Initial_Height *(e)^(k*x)

Initial_Height  = 64 ft

Second bounce

x  = 2

36 ft = 64 ft *(e)^(2*k)

(e)^(2*k) = 0.5625

2* k = ln(0.5625)

k = -0.2877

Fourth bounce

x =  4

Height = 64 *(e)^(-0.2877*(4))

Height  = 20.248 ft

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Allyson Greve has calculated her federal taxable income to be $45,300. She pays a state income tax rate of 3% on her federal tax
valentinak56 [21]

Answer:

1,359

Step-by-step explanation:

3% of 45,300 is 1,359

4 0
3 years ago
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lesantik [10]

two !

hAhA jK iTs 75

6 0
3 years ago
What is -1060 degrees in radians
mart [117]
-18.5004901 that’s the answer! Hope this helps!
7 0
3 years ago
The height h in feet of the ball t seconds after it is kicked can be modeled by the function h = -4t (4t - 11). How long is the
Vaselesa [24]

Answer:

t₁  = 2,75 sec

Step-by-step explanation:

The ball will get h maximum when  dh/dt ( its vertical component of the speed is equal to 0. At this moment the ball has flown half of the total flight time

Then

h(t)  = - 4t * ( 4*t - 11 )

h(t)  = - 16*t² + 44*t

Taking derivatives on both sides of the equation we get:

dh/dt  =  - 32*t  +  44

dh/dt  = 0     ⇒   -32*t  + 44 = 0

t  =  44/32     ⇒   t = 1,375 s

So twice this time

2*t   =  2 * 1.375

Total time t₁  = 2,75 sec

6 0
3 years ago
What is the solution to the system of equations????
prohojiy [21]
First of all, we can solve this by elimination (adding the 2 equations and eliminating 1 variable).
3x+10y=-47
5x+7y=40
It looks like we can eliminate the x by making one 15x, and the other -15x (15 is the least common multiple [LCM] of 3 and 5).
5 (3x+10y=-47) --> 15x+50y=-235
-3 (5x+7y=40) --> -15x-21y=-120
15x-15x = 0, 50y-21y = 29y, -235-120 = -355
0 + 29y = -355
29y/29 = -355/29
y = 12.24
then plugged that into 3x+10y=-47
3x+122.4=-47
3x+122.4-122.4=-47-122.4
3x = -169.4
x = 56.47
Something is wrong... are you sure the 2nd equation wasn't equal to NEGATIVE 40??
Or the 1st one equal to POSITIVE 40??
3 0
3 years ago
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