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salantis [7]
3 years ago
12

Brady dropped a bouncy ball from a height of 64 feet. After the second bounce, the ball reached a height of 36 feet. write a rul

e to represent the height of the ball after each bounce, then find the height after the fourth bounce
Mathematics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

Height  = 20.248 ft

Step-by-step explanation:

We can model this process with an exponential function

Height = Initial_Height *(e)^(k*x)

Initial_Height  = 64 ft

Second bounce

x  = 2

36 ft = 64 ft *(e)^(2*k)

(e)^(2*k) = 0.5625

2* k = ln(0.5625)

k = -0.2877

Fourth bounce

x =  4

Height = 64 *(e)^(-0.2877*(4))

Height  = 20.248 ft

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3 out of five picks are orange . If 12 picks are orange , how many picks are there in all?
tekilochka [14]

20 picks in total .

8 0
3 years ago
A, B and C are collinear points. B is between A and C. AB=12 BC=18 AC=3x Find X.
SCORPION-xisa [38]

Answer:

x =10

Step-by-step explanation:

Given

AB = 12

BC = 18

AC = 3x

Required

Solve for x

Since B is in between both points, then:

AC = AB + BC

This gives

3x = 12 + 18

3x = 30

Divide by 3

x =10

3 0
3 years ago
One of the earliest applications of the Poisson distribution was in analyzing incoming calls to a telephone switchboard. Analyst
grandymaker [24]

Answer:

(a) P (X = 0) = 0.0498.

(b) P (X > 5) = 0.084.

(c) P (X = 3) = 0.09.

(d) P (X ≤ 1) = 0.5578

Step-by-step explanation:

Let <em>X</em> = number of telephone calls.

The average number of calls per minute is, <em>λ</em> = 3.0.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.0.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...

(a)

Compute the probability of <em>X</em> = 0 as follows:

P(X=0)=\frac{e^{-3}3^{0}}{0!}=\frac{0.0498\times1}{1}=0.0498

Thus, the  probability that there will be no calls during a one-minute interval is 0.0498.

(b)

If the operator is unable to handle the calls in any given minute, then this implies that the operator receives more than 5 calls in a minute.

Compute the probability of <em>X</em> > 5  as follows:

P (X > 5) = 1 - P (X ≤ 5)

              =1-\sum\limits^{5}_{x=0} { \frac{e^{-3}3^{x}}{x!}} \,\\=1-(0.0498+0.1494+0.2240+0.2240+0.1680+0.1008)\\=1-0.9160\\=0.084

Thus, the probability that the operator will be unable to handle the calls in any one-minute period is 0.084.

(c)

The average number of calls in two minutes is, 2 × 3 = 6.

Compute the value of <em>X</em> = 3 as follows:

<em> </em>P(X=3)=\frac{e^{-6}6^{3}}{3!}=\frac{0.0025\times216}{6}=0.09<em />

Thus, the probability that exactly three calls will arrive in a two-minute interval is 0.09.

(d)

The average number of calls in 30 seconds is, 3 ÷ 2 = 1.5.

Compute the probability of <em>X</em> ≤ 1 as follows:

P (X ≤ 1 ) = P (X = 0) + P (X = 1)

             =\frac{e^{-1.5}1.5^{0}}{0!}+\frac{e^{-1.5}1.5^{1}}{1!}\\=0.2231+0.3347\\=0.5578

Thus, the probability that one or fewer calls will arrive in a 30-second interval is 0.5578.

5 0
3 years ago
Lesson 5: Lines and Triangles Geometry A Unit 4: Parallel and Perpendicular Lines
aev [14]
The Triangle Sum Theorem states that the sum of the angles of a triangle equal 180°. 
Therefore,
45° + 62° + k = 180
   107°      + k = 180
                   k  = 73°
The value of k is 73°
3 0
3 years ago
Read 2 more answers
★彡[ʜᴇʟʟᴏ ᴇᴠᴇʀʏʙᴏᴅʏ ɪ ᴀᴍ ꜰʀᴏᴍ ɪɴᴅɪᴀ ᴀɴʏᴏɴᴇ ᴡʜᴏ ᴄᴀɴ ʙᴇᴄᴏᴍᴇ ᴍʏ ɢɪʀʟꜰʀɪᴇɴᴅ
Ivanshal [37]

Answer:

No

Step-by-step explanation:

6 0
3 years ago
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