Answer:
im 95% sure the answer is 6
Step-by-step explanation:
when i wrote it down it just never came out to one of thoes answers, but 6 was the closest
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
141.5 in
Step-by-step explanation
AB // CD // EF
12 / 15 = 21 / y (By the property of 3 parallel lines and its transversals)
y = (15*21) / 12 = 26.25
CD // EF // GH
21 / y = x / 10 21 / 26.25 = x / 10
x = (21*10) / 26.25
x = 8
perimeter of ABHG = (y-14) +15 + y + 10 + (5x-3) + x + 21 + 12 = 141.5
Answer:
The money she will end up earning in interest on the cd = $11,352.90
Step-by-step explanation:
The formula for getting the accumulated amount(compounded) is;

Where
A = Accumulated amount
P = principle (deposit)
r = interest rate and
n = no of times interest applied per time period.
The interest is compounded quarterly so in one year it will be 4 times
In 5 years
n = (5×4)-3 = 17 (as she will withdraw 3 month before the completion of five years)
A =
^17
= 7100( 1 + 0.028)^17
= 7100(1.028)^17
= 7100 * 1.599
= 11,352.90
Therefore the money she will end up earning in interest on the cd = $11,352.90
Answer:
20% off 45.00 is 36.00
Step-by-step explanation:
The difference is $9.00