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BartSMP [9]
3 years ago
11

The relationship between the number of hours a plumber works and the total work fee she charges is proportional. Her fee for 5 h

ours of work is $350. Which of the fallowing could be combination of values for the plumbers work hours and total work fee she charges ?
Mathematics
1 answer:
Mashcka [7]3 years ago
4 0

Answer: $70 per hour

Step-by-step explanation:

Hi, to answer this question we have to calculate the hourly fee.

To do this, we simply have to divide the 5 hour fee price (350) by the number of hours worked.(5):

Mathematically speaking:

350/5 = $70 per hour

So, since the work fee is proportional, for x hours, the expression is:

70x

Feel free to ask for more if needed or if you did not understand something.

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Consider the sequence 3, 6, 12, 24, 48......
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Verify a(b-c)=ab-ac for a=1.6;b=1/-2;&amp; c=-5/-7​
harina [27]

Given:

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

To verify:

a(b-c)=ab-ac for the given values.

Solution:

We have,

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

We need to verify a(b-c)=ab-ac.

Taking left hand side, we get

a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)

a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)

Taking LCM, we get

a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)

a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)

a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)

a(b-c)=-\dfrac{68}{35}\right)

Taking right hand side, we get

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ab-ac=\dfrac{-68}{35}

Now,

LHS=RHS

Hence proved.

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