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Lerok [7]
3 years ago
6

Jose practiced piano 5 days this week. He practiced 3/4 of an hour each day.

Mathematics
2 answers:
Ann [662]3 years ago
6 0
I like working with decimals better so I changed 3/4 to a fraction by dividing 3 by 4. I get 0.75.

Multiply 0.75 by 5 and you will get 3.75. Now remember it’s time so 0.75 of an hour is 45 minutes.

The answer is 3 hours and 45 minutes.
emmainna [20.7K]3 years ago
3 0

Answer:

3 hours and 15 min is how long he practiced

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<u>Answer:</u>

When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules

<u>Solution:</u>

We know \text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})\times\text { Distance (D) }

Anne is pushing the wheelbarrow with a force of 70 N at an angle of 50^{\circ} with the horizontal

So the force of Anne will be F=70 \cos 50^{\circ}=(70 \times 0.64)=44.8 \mathrm{N}

She pushes the wheelbarrow 25 meter, So D = 25 meters

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Answer:

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3 years ago
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A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.
Vlada [557]

Answer:

a)  y=12000(2)^{\frac{t}{50}}

b)  Approx. 27,569 bacteria

c)  About 103 minutes

Step-by-step explanation:

a)

This will follow exponential modelling with form of equation shown below:

y=Ab^{\frac{t}{n}}

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}

b)

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>

<u></u>

c)

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103

After about 103 minutes, there will be 50,000 bacteria

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