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kumpel [21]
3 years ago
9

Distribute and Combine Like Terms 11(2t - 4) + 6t - 6

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0
It’s actually 28t - 10

11(2t-4)+6t-6
22t-4+6t-6 add 22t and 6t
28t-4-6 combine -4 & -6
28t-10
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3x-2(x+3)=4x-9-x is the question
kozerog [31]

Answer:

\large\boxed{x = 7}

Step-by-step explanation:

3x - 2(x + 3) = 4x - 9 - x

Start by multiplying 2 by the values in the parenthesis

3x - 2x + 6 = 4x - 9 - x

Subtract 3x - 2x and 4x - x

x + 5 = 3x - 9

Add 9 to both sides of the equation

x + 14 = 3x

Subtract x from both sides of the equation

14 = 2x

Divide both sides of the equation by 2

\large\boxed{x = 7}

Hope this helps :)

8 0
4 years ago
5 ( x + y) +3 (2x +y)​
satela [25.4K]

Answer:

11x + 8y

Step-by-step explanation:

(5x + 5y) + 3 ( 3 · 2x + 3y)

(5x + 5y) + (6x + 3y)

5x + 5y + 6x + 3y

5x + 6x + 5y + 3y

11x + 8y

7 0
2 years ago
How many sides does a polygon gave
zalisa [80]
A polygon has 5 sides
5 0
3 years ago
Read 2 more answers
Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

The difference is: 11x+85

( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

h=9

b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

V=\pi r^2h

V=\pi (2.5)^2 \cdot 5

V=31.25 \pi

V_{c} \approx 98.17 \text{ m}^3

The volume of the sphere:

$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

The volume of the capsule is approximately 163.57  \text{ m}^3

3 0
4 years ago
The original price is $40.90 and the sale price is 30% off what would be two different expressions for the equation?
Ann [662]

Answer:

(40.90 ÷ 100) × 30

And

0.3 × 40.90

8 0
3 years ago
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