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alexdok [17]
3 years ago
13

The drama teacher decreased the length of a play from 90 minutes to 60 minutes. What was the percent decrease in the length of t

he play?
Please help I need this for a test asapppp and pleased include the solving for this question I need to submit the work
Mathematics
1 answer:
algol133 years ago
4 0

Answer:

It was a 33% decrease

Step-by-step explanation:

90 minutes - 60 minutes = 30 minutes

30/90= .333333333333

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Every year the Lee family has a big family dinner, and everyone brings a mug to exchange. The mugs are put on wooden hangers on
RideAnS [48]

Answer:

21 more mugs were brought this year than last year.

Step-by-step explanation:

We can solve by subtracting the initial amount of mugs from the final amount of mugs.

To find the amount of mugs hung up this year, we will use the equation: m = 12w where m = the number of mugs & w = the number of wooden hangers. The 12 represents the amount of mugs per wooden hanger.

We can plug in 3 for w since 3 wooden hangers were filled up and we would get 12(3) = m = 36 mugs

Now we subtract last year's total mugs hung up from this year's total mugs hung up.

We end up with 36 - 15 = 21

4 0
2 years ago
A 9 3/5 inch long pipe is cut into eight equal length pieces. How long is each piece?
Alenkinab [10]

Answer:

1.2

Step-by-step explanation:

9 3/5 divided by 8


3 0
4 years ago
A sample is selected from a population with μ = 46, and a treatment is administered to the sample. After treatment, the sample m
Georgia [21]

Answer:

0.5

Step-by-step explanation:

Solution:-

- The sample mean before treatment, μ1 = 46  

- The sample mean  after treatment, μ2 = 48

- The sample standard deviation σ = √16 = 4

- For the independent samples T-test, Cohen's d is determined by calculating the mean difference between your two groups, and then dividing the result by the pooled standard deviation.

                           Cohen's d = \frac{u2 - u1}{sd_p_o_o_l_e_d}

- Where, the pooled standard deviation (sd_pooled) is calculated using the formula:

                          sd_p_o_o_l_e_d =\sqrt{\frac{SD_1^2 +SD_2^2}{2} }

- Assuming that population standard deviation and sample standard deviation are same:

                          SD_1 = SD_2 =  σ = 4

- Then,

                           sd_p_o_o_l_e_d =\sqrt{\frac{4^2 +4^2}{2} } = 4

- The cohen's d can now be evaliated:

                          Cohen's d = \frac{48 - 46}{4} = 0.5

6 0
3 years ago
I =125 r=6% t=1 what is p
vfiekz [6]
There is no P in here, you can't solve for P without a P, Or I just don't get the question.
4 0
3 years ago
Maria measured a centipede that was 1 1/12 inches long. Jerome measured a centipede that was 11/12 of an inch long. How much lon
4vir4ik [10]

Answer:

1/6

Step-by-step explanation:

The centipede that Maria measured was 1 1/12 inches long. If you convert this to an improper fraction it is equal to 13/12 inches. Now to find how much longer Maria's centipede was than Jeromes, you just take 11/12 and minus it from 13/12 which is equal to 2/12 of an inch, which then simplifies to 1/6 of an inch.

3 0
3 years ago
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