All categories

3 years ago

True or false? the point at which a tangent line meets a circle is called the point of tangency

Mathematics

2 answers:

kherson [118]3 years ago

7 0

Answer:

true is the answer

Step-by-step explanation:

gregori [183]3 years ago

5 0

(breaths in) True, The point at which the circle and the line intersect is the point of tangency.

You might be interested in

(5 marks)

Shtirlitz [24]

I thought this right but sorry if it is wrong

first make the 6% in amount by 6×10,000÷100=3600

then, the convert 4 year into month by (4×12)=48month. after that divide 48months by 4 month.i.e.48÷4=12.at last multiply 12 by 3600.i.e. 12×3600=43200

3 0

3 years ago

A bicycle store costs $3150 per month to operate. The store pays an average of $65 per bike. The average selling price of each

OLga [1]

Answer: 35

Step-by-step explanation:

-3150M-65b+155b

-3150m+92b

3150/92= 34.23913043 so about 35

6 0

3 years ago

Eight less then a number is seventy five

Tom [10]

83 is your answer you simply do the oppisite and instesad of subtracting the number you add it to the result being 75

5 0

3 years ago

Help on a time limit!

hichkok12 [17]

C I petty sure the answer is c

4 0

2 years ago

A freshly inoculated bacterial culture of Streptococcus contains 100 cells. When the culture is checked 60 minutes later, it is

Luba_88 [7]

Answer:

$P(t) = 100e^{0.0251t}$

The doubling time is of 27.65 minutes.

Step-by-step explanation:

Exponential equation of growth:

The exponential equation for population growth is given by:

$P(t) = P(0)e^{kt}$

In which P(0) is the initial value and k is the growth rate.

A freshly inoculated bacterial culture of Streptococcus contains 100 cells.

This means that $P(0) = 100$ . So

$P(t) = 100e^{kt}$

When the culture is checked 60 minutes later, it is determined that there are 450 cells present.

This means that $P(60) = 450$ , and we use this to find k. So

$450 = 100e^{60k}$

$e^{60k} = 4.5$

$\ln{e^{60k}} = \ln{4.5}$

$60k = \ln{4.5}$

$k = \frac{\ln{4.5}}{60}$

$k = 0.0251$

$P(t) = 100e^{0.0251t}$

Doubling time:

This is t for which P(t) = 2P(0) = 200. So

$200 = 100e^{0.0251t}$

$e^{0.0251t} = 2$

$\ln{e^{0.0251t}} = \ln{2}$

$0.0251t = \ln{2}$

$t = \frac{\ln{2}}{0.0251}$

$t = 27.65$

The doubling time is of 27.65 minutes.

7 0

3 years ago