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3 years ago

Suppose the goal for mr. Luockwoods class had been 250 cans. Then 550 cans would have been what percent of the goal?

Mathematics

1 answer:

ser-zykov [4K]3 years ago

3 0

220% of the goal. This is because 500 cans would be 200% but since it’s 550, the extra 50% would equal to 220%.

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Mamont248 [21]

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3 years ago

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3 years ago

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A boat crew rowed 10.5 miles downstream, with the current, in 1.5 hours. the return trip upstream , against the current , covere

alukav5142 [94]

Answer:

The speed of the boat is 5 miles per hours

The speed of the current is 2 miles per hours .

Step-by-step explanation:

Given as :

The distance cover by boat downstream = D = 10.5 miles

The time taken by boat to cover D distance = T = 1.5 hours

The distance cover by boat Upstream = d = 10.5 miles

The time taken by boat to cover d distance = t = 3.5 hours

Let The speed of boat = x mph

Let The speed of current = mph

Now, According to question

∵ Speed = $\dfrac{Distance}{Time}$

<u>For Downstream</u>

x + y = $\dfrac{D}{T}$

Or, x + y = $\dfrac{10.5}{1.5}$

Or, x + y = 7 .......A

<u>For Upstream</u>

x - y = $\dfrac{d}{t}$

Or, x - y = $\dfrac{10.5}{3.5}$

Or, x - y = 3 .......B

Now, Solving eq A and eq B

So, (x + y) + (x - y) = 7 + 3

Or, (x + x) + (y - y) = 10

Or, 2 x + 0 = 10

∴ x = $\dfrac{10}{2}$

i.e x = 5 mph

So, The speed of the boat = x = 5 miles per hours

Put the value of x into eq A

∵ x + y = 7

Or, 5 + y = 7

∴ y = 7 - 5

i.e y = 2 mph

So, The speed of the current = y = 2 miles per hours

Hence, The speed of the boat is 5 miles per hours and The speed of the current is 2 miles per hours . Answer

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3 years ago

In a random sample of males, it was found that 28 write with their left hands and 210 do not. In a random sample of females, it

Drupady [299]

Answer:

a) Null hypothesis: $p_{M} \geq p_{W}$

Alternative hypothesis: $p_{M} < p_{W}$

b) $z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271$

c) $p_v =P(Z$

d) If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of men that write with their left hand is NOT significant lower than the proportion of female that write with their left hand

Step-by-step explanation:

1) Data given and notation

$X_{M}=28$ represent the number of men that write with their left hand

$X_{W}=62$ represent the number of women that write with their left hand

$n_{M}=210+28=238$ sample of male selected

$n_{W}=62+435=497$ sample of female selected

$p_{M}=\frac{28}{238}=0.118$ represent the proportion of men that write with their left hand

$p_{W}=\frac{62}{497}=0.125$ represent the proportion of women that write with their left hand

$\alpha=0.05$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the rate of left-handedness among males is less than that among females , the system of hypothesis would be:

Null hypothesis: $p_{M} \geq p_{W}$

Alternative hypothesis: $p_{M} < p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{28+62}{238+497}=0.122$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271$

4) Statistical decision

We have a significance level provided $\alpha=0.05$ , and now we can calculate the p value for this test.

Since is a one left side test the p value would be:

$p_v =P(Z$

If we compare the p value and the significance level given $\alpha=0.05, 0,1,0.15$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of men that write with their left hand is NOT significant loer than the proportion of female that write with their left hand .