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Misha Larkins [42]
3 years ago
12

A 1.5 kilogram lab cart accelerated unitorily from rest to a speed of 2.0 meters per second in 0.50 second What is the magnitude

of the force that produced this acceleration?
Mathematics
1 answer:
NISA [10]3 years ago
3 0
Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning.

The cart's acceleration is

(0 - 2 m/s) / (0.3 sec)

= ( -2 / 0.3 ) (m/s²) = -(6 and 2/3) m/s² .

Newton's second law of motion says

Force = (mass) x (acceleration) .

For this cart: Force = (1.5 kg) x ( - 6-2/3 m/s²)

= ( - 1.5 x 20/3 ) (kg-m/s²)

= - 10 newtons .

The force is negative because it acts opposite to the direction
in which the cart is moving, it causes a negative acceleration,
and it eventually stops the cart.
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the volume of a cone is 120 cubic centimeters. the height of the cone is 4.5 centimeters. determine the radius of a cone
kolbaska11 [484]
<h3> given:</h3>

<u>v = 120 \:  {cm}^{3}</u>

<u>h = 4.5 \: cm</u>

<h3>to find:</h3>

the radius of the cone.

<h3>solution:</h3>

r =  \sqrt{3 \frac{v}{\pi \: h} }

r =  \sqrt{3  \times   \frac{120}{\pi \times 4.5} }

r = 5.04627 \: cm

r = 5.05 \: cm

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>is</u><u> </u><u>5.05</u><u> </u><u>centimeters</u><u>.</u>

7 0
2 years ago
Please help me!!! Brainliest
Luba_88 [7]
The lines are parallel.

In order to figure this out, let's start off by simplifying both equations as much as we can:
2y = 16 + 4x
Divide by 2
y = 2x + 8

Remember that the slope of that equation is '2' since 'm' in the equation y = mx + b represents slope.

Simplify the next equation:
6y - 30 = 12 x
6y = 12x + 30
Divide by 6:
y = 2x + 5

As you can tell, this line also has a slope of 2.
Parallel lines is defined as two lines that have the same slope. Knowing this, we can infer that these two lines are parallel.

-T.B.
7 0
3 years ago
BRAINLIEST!!PLEASE HELP ME!!
Arisa [49]

The answer is a. You have the correct one highlighted I believe.

Hope this helps.

7 0
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How do I find the slope of this altitude?<br><br>I am referring to question 19.
Crazy boy [7]
The altitude's slope must be perpendicular to that of the line. 

The slope of segment BC is 2/5. The slope of the altitude must be perpendicular to 2/5. Since the negative reciprocal of 2/5 is -5/2, then the slope of the altitude is -5/2. 
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3 years ago
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I need help with this plz.
valina [46]

Answer:

what do u need help with?

Step-by-step explanation:

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