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Misha Larkins [42]
2 years ago
12

A 1.5 kilogram lab cart accelerated unitorily from rest to a speed of 2.0 meters per second in 0.50 second What is the magnitude

of the force that produced this acceleration?
Mathematics
1 answer:
NISA [10]2 years ago
3 0
Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning.

The cart's acceleration is

(0 - 2 m/s) / (0.3 sec)

= ( -2 / 0.3 ) (m/s²) = -(6 and 2/3) m/s² .

Newton's second law of motion says

Force = (mass) x (acceleration) .

For this cart: Force = (1.5 kg) x ( - 6-2/3 m/s²)

= ( - 1.5 x 20/3 ) (kg-m/s²)

= - 10 newtons .

The force is negative because it acts opposite to the direction
in which the cart is moving, it causes a negative acceleration,
and it eventually stops the cart.
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A screening test for a newly discovered disease is being evaluated for its performance as a screening test. In order to determin
Elena-2011 [213]

Answer:

- Sensitivity = 62.7 %

- specificity = 74.9 %

- positive predictive value = 45.2 %

- negative predictive value = 85.9 %

- Accuracy of the test = 71.9 %

Step-by-step explanation:

Given the data in th question;

                                 CONDITION POSITIVE    CONDITION NEGATIVE   TOTAL

TEST POSITIVE                   42                                       51                            93

TEST NEGATIVE                 25                                      152                          177

TOTAL                                  67                                     203                         270

so; A=42, B=51, C=25 and D=152

Sensitivity = [A / ( A + C) ]×100= [42 /( 42 + 25)]×100 = [42 / 67] 100=

Sensitivity = 62.7 %

specificity = [D / ( D + B) ]×100= [152 /( 152 + 51)]×100 = [152 / 203] 100=

specificity = 74.9 %

positive predictive value = [A / ( A + B) ]×100 = [42 /( 42 + 51)]×100 =[42/93] 100

positive predictive value = 45.2 %

negative predictive value =  [D / ( D + C) ]×100 = [152 /( 152 + 25)]×100 =[152/177] 100

negative predictive value = 85.9 %

Accuracy of the test = [A + D / ( A+B+C+D)] =  [42 + 152 / ( 42+51+25+152)]

= [ 194 / 270 ]

Accuracy of the test = 71.9 %

3 0
2 years ago
Solve for x: 3x − 2 > 5x + 10. (5 points)
Galina-37 [17]

Answer:

x < -6

Step-by-step explanation:

3x - 2 > 5x + 10

first step is to isolate x

3x -2 >5x +10

3x > 5x + 10 + 2

3x -5x > 10 + 2

now that we have 3x and -5x we can combine them

-2x > 10 + 2

now add 10 +2 =12

-2x > 12 (now divide by -2)

x < -6 (when we divide we flip the inequality sign)

5 0
3 years ago
Given this unit circle, what is the value of x? (x, -7/10)(1,0)​
Paraphin [41]

Answer:

x = - \frac{\sqrt{51} }{10}

Step-by-step explanation:

the equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

The radius of a unit circle is r = 1

substitute (x, - \frac{7}{10} ) into the equation and solve for x

x² + (- \frac{7}{10} )² = 1²

x² + \frac{49}{100} = 1 ( subtract \frac{49}{100} from both sides )

x² = 1 - \frac{49}{100} = \frac{51}{100} ( take square root of both sides )

x = ± \sqrt{\frac{51}{100} } = ± \frac{\sqrt{51} }{10}

since the point is in the 3rd quadrant then x < 0

x = - \frac{\sqrt{51} }{10}

5 0
2 years ago
A Sum of $14 is made of 92 coins consisting of dimes and quarters. How Many are there of each kind of coin
steposvetlana [31]
So first I would say, what if all of them were dimes, how far away would it be from $14?

So 92 coins * 10 cents = $9.20

So it's 4.80 dollars away from 14 dollars.

So if we were to switch one to a quarter, it would increase by 0.15 cents.

So we want to see how many increases we need to reach 4.80 dollars more.

4.80/0.15 = 32

So there are 32 quarters and 60 dimes.
7 0
3 years ago
Read 2 more answers
Help please tell me what the answer is ASAP
Amiraneli [1.4K]

Answer:

The approximated length of EF is 2.2 units ⇒ A

Step-by-step explanation:

<em>The tangent ratio in the right triangle is the ratio between the opposite side to the adjacent side of one of the acute angle in the triangle</em>

In the given figure

∵ The triangle DFE has a right angle F

∵ The opposite side to angle D is EF

∵ The adjacent side to angle D is DF

→ By using the tangent ratio above

∴ tan(∠D) = \frac{EF}{DF}

∵ DF = 6 units

∵ m∠D = 20°

→ Substitute then in the ratio above

∴ tan(20°) = \frac{EF}{6}

→ Multiply both sides by 6

∴ 6 tan(20°) = EF

∴ 2.183821406 = EF

→ Approximate it to the nearest tenth

∴ 2.2 = EF

∴ The approximated length of EF is 2.2 units

7 0
2 years ago
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