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lesya692 [45]
3 years ago
15

HELP PLEEEASEEE

Mathematics
1 answer:
ohaa [14]3 years ago
6 0
PeRIMeter is the RIM around the rectangle.
P= 3.2+1.5+3.2+1.5= 6.4+ 3= 9.4 m

Area is A= 3.2• 1.5= 4.8 m^2
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4. What number completes the following<br>equation?<br>8x (40 + 7) = (8 ) + (8 x 7)​
Juli2301 [7.4K]

Answer:

x=8/47

Step-by-step explanation:

8x(40+7)=8+(8*7)

8x(47)=8+56

376x=64

x=64/376

x=8/47

5 0
3 years ago
Garden A has 9 more currant bushes than Garden B. If 3 currant bushes are transplanted from Garden B to Garden A, then Garden A
marusya05 [52]

Answer:

42

Step-by-step explanation:

Let x = the original number of bushes in garden A

Let x-9 = the original number of bushes in garden B

x-9-3=x-12 = bushes in garden B after transplanting 3

x+3 = bushes in garden A after transplanting 3

x+3=1.5(x-12)

x+3=1.5x-18

0.5x=21

x=42

There were 42 current bushes in garden A

3 0
3 years ago
Read 2 more answers
Which of the following are not affected by the others outcomes
tankabanditka [31]
Whats not affected by the
others outcome
6 0
3 years ago
A number is picked randomly in the range [0,7]. What is the probability that the number picked is between 3 and 5? What is the p
emmasim [6.3K]

Answer:

(1) 0.125

(2) 0.125

Step-by-step explanation:

The total number of possible outcomes is:

N = 8

(1)

Compute the probability that the number picked is between 3 and 5 as follows:

Number of Favorable outcomes = 1

The probability is:

P (Number picked is between 3 and 5) = 1/8 = 0.125

Thus, the probability that the number picked is between 3 and 5 is 0.125.

(2)

The number usually picked appears to be in in the range [3,5], i.e. the numbers could be, {3, 4 or 5}.

Number of Favorable outcomes = n (Number < 4 and within [3, 5]) = 1

P (less than 4 ∩ within [3, 5]) = 1/8 = 0.125

Thus, the probability that the number picked is less than 4 knowing that the number usually picked appears to be in in the range [3,5] is 0.125.

4 0
3 years ago
Sum of all natural numbers from100to300 which are divisible by 4and 5 is​
My name is Ann [436]

If x is a number that is both divisible by 4 and 5, then

\begin{cases}x\equiv0\pmod4\\x\equiv0\pmod5\end{cases}

4 and 5 are coprime, so we can use the Chinese remainder theorem to solve this system and find that x=20n is a solution to the system, where n is any integer. Simply put, any multiple of 20 fits the bill.

Now, there are 11 numbers between 100 and 300 that are divisible by 20 (100, 120, 140, and so on). We have 20n=100 when n=5, so the sum we want to compute is

\displaystyle\sum_{n=5}^{15}20n=\boxed{2200}

4 0
3 years ago
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