$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$

8 0

3 years ago

The formula for the circumference of a circle is c= 2pi r, where r is the radius. Rearrange the formula to solve for our and sel

ratelena [41]

Answer: r = C/(2pi)

This is the same as writing $r = \frac{C}{2\pi}$

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Explanation:

pi is some number (approximately 3.14) which means 2pi is also some number (roughly 6.28)

Saying c = 2pi*r means we have 2pi times r, and the result is the circumference c. To isolate r, we'll undo the multiplication. We'll undo it by dividing both sides by 2pi like so

C = 2pi*r

C/(2pi) = r

r = C/(2pi)

in which we can write it like $r = \frac{C}{2\pi}$

So whatever C is, we divide it over 2pi (aka roughly 6.28) to get the radius.

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Extra Info (Optional Section):

As an example, let's say the circumference of the circle is 628 feet. This means the distance around the circle is 628 feet. So C = 628 would lead to...

r = C/(2pi)

r = C/(6.28)

r = 628/(6.28)

r = 100

So the radius would be roughly 100 feet.

8 0

3 years ago