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Mkey [24]
3 years ago
5

The Yu family and the Sainz family went on vacation together and each family leased a car. The leasing company charged a flat re

ntal fee for the week, plus a charge for each mile driven. The Yu's drove 222 miles; their car cost $110.30 for the week. The Sainz's drove 147 miles; their car cost $99.05. What is the linear equation that represents the cost of a rental car? Round to the nearest hundredth
Mathematics
1 answer:
Dafna11 [192]3 years ago
7 0

Answer:

y = 0.15x+77 is the equation linear connecting total cost y and miles driven x

Step-by-step explanation:

Given that the leasing company charged a flat rental fee for the week, plus a charge for each mile driven.

Let flat rental fee be c and cost per mile driven = m and miles driven = x

Total cost =y

Then y = mx+C is the linear equation.

to find m and c, we use the fact that y =110.30 when x = 222

i.e. 110.30 = c+222x

and similarly 99.05 = c+147x

Subtract to eliminate c

11.25 = 75 x

0.15 =x

Substitute in I equation

110.30 = c+222(0.15)

c = 77

Hence y = 0.15x+77 is the equation linear connecting total cost y and miles driven x

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37.5 to the nearest degree
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38 degrees

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Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph.
Lelechka [254]

Answer:

Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)

Parallel: slopes both = -1/3

1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.

I will show the work for both the problems down below.

Step-by-step explanation:

Finding coordinates:

1+(-5)/2=-2  5+1/2=3

(-2,3)

1+4/2= 2.5   5+(-2)/2= 1.5

(2.5,1.5)

Show work verifying the EG and BC are parallel:

You can do this by finding the slope

Slop formula (y2-y1)/(x2-x1)

(1.5-3)/(2.5-(-2))

Then simplify

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Show work verifying that EG and BC are parallel:

Use distance formula to find how long each line is

√(x2-x1)^2+(y2-y1)^2

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7 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPP
AlexFokin [52]

Answer:

A. x= 3, y= -2

Step-by-step explanation:

[2] 2x= 4y+14

[1] 3y+5x=9

Solve equation [2] for the variable  x

 [2]    2x = 4y + 14

 [2]    x = 2y + 7

// Plug this in for variable  x  in equation [1]

  [1]    5•(2y+7) + 3y = 9

  [1]    13y = -26

// Solve equation [1] for the variable  y

  [1]    13y = - 26

  [1]    y = - 2

// By now we know this much :

   x = 2y+7

   y = -2

// Use the  y  value to solve for  x

   x = 2(-2)+7 = 3

good luck, I hope this helps!!!

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Your answer is:
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