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3 years ago

If 4a - 3 = 9, what is the value of 4a + 1?! A: 13 B: 3 C:49 D: 5

Mathematics

2 answers:

Debora [2.8K]3 years ago

7 0

Answer:

A: 13

Step-by-step explanation:

4a-3 = 9

add 3 to both sides

4a-3 = 9

+3 +3

the -3 and +3 will cancel each other out

and from adding the 3 to the 9 will turn the 9 into 12!

Now your equation will look like this

4a = 12

Next divide both sides by 4. the 4 will cancel out the other 4.\

now you will have your answer

a = 3

so now substitute the A with 3 in

4a+1

so it will be

4(3)+1

4 times 3 is equal to 12

then 12+1 = 13

I hope this helps! :)

Oliga [24]3 years ago

6 0

Answer:

a=3

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Which is a correct first step in solving 5 - 2x < 8x - 3?

charle [14.2K]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What are the solutions of the equation x4 + 95x2 – 500 = 0? Use factoring to solve. x = plus-or-minus StartRoot 5 EndRoot and x

Oduvanchick [21]

Answer:

* x ⇒ plus-or-minus StartRoot 5 EndRoot and ±10i *

Step-by-step explanation:

Through factorization;

x^4 + 95x^2 – 500 = 0, ⇒ u^2 ⇒ x^2,

u^2 + 95u - 500 = 0, ⇒ factors of -500; -25, 20, -50 * 10, -2 * 250, -5 * 100...

( u )^2 + ( - 5 + 100 ) + ( - 5 * 100 ) = 0,

( u - 5 )( u + 100 ) = 0,

u = 5, and y = - 100

Substitute u back into format x^2;

u = x^2, 5 = x^2, | x | = √5 ⇒ x = - / + √5,

u = x^2, - 100 = x^2, | x | = √- 100 ⇒ x = - / + 10i

* Answer: x ⇒ plus-or-minus StartRoot 5 EndRoot and ±10i *

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3 years ago