She has 10lbs of 25% syrup... so, in the 10lbs, 25% of that is syrup, the rest, namely the 75% remaining is water or other substances.
let's say she adds "x" lbs of water, to get "y" lbs for the 10% mixture.
how much is 25% of 10lbs? well, (25/100) * 10, or 2.5.
the water has no sugar syrup in it, so is just pure water, so the amoun of syrup in it is 0%, how much is 0% of "x" lbs? well, (0/100) * x, or 0.00x, which is just 0.
how much is 10% of "y" lbs? well (10/100) * y, or 0.10y.
whatever "x" and "y" are, we know that 10 + x = y.
we also know that the syrup amount in that is also 2.5 + 0.00x = 0.10y, thus
Answer:
{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x
4
+4x
3
y+6x
2
y
2
+4xy
3
+y
4
Step-by-step explanation:
1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)
2
=a
2
+2ab+b
2
.
({x}^{2}+2xy+{y}^{2})({x}^{2}+2xy+{y}^{2})(x
2
+2xy+y
2
)(x
2
+2xy+y
2
)
2 Expand by distributing sum groups.
{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x
2
(x
2
+2xy+y
2
)+2xy(x
2
+2xy+y
2
)+y
2
(x
2
+2xy+y
2
)
3 Expand by distributing terms.
{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x
4
+2x
3
y+x
2
y
2
+2xy(x
2
+2xy+y
2
)+y
2
(x
2
+2xy+y
2
)
4 Expand by distributing terms.
{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}({x}^{2}+2xy+{y}^{2})x
4
+2x
3
y+x
2
y
2
+2x
3
y+4x
2
y
2
+2xy
3
+y
2
(x
2
+2xy+y
2
)
5 Expand by distributing terms.
{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}{x}^{2}+2{y}^{3}x+{y}^{4}x
4
+2x
3
y+x
2
y
2
+2x
3
y+4x
2
y
2
+2xy
3
+y
2
x
2
+2y
3
x+y
4
6 Collect like terms.
{x}^{4}+(2{x}^{3}y+2{x}^{3}y)+({x}^{2}{y}^{2}+4{x}^{2}{y}^{2}+{x}^{2}{y}^{2})+(2x{y}^{3}+2x{y}^{3})+{y}^{4}x
4
+(2x
3
y+2x
3
y)+(x
2
y
2
+4x
2
y
2
+x
2
y
2
)+(2xy
3
+2xy
3
)+y
4
7 Simplify.
{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x
4
+4x
3
y+6x
2
y
2
+4xy
3
+y
4
Answer:
The Cohen's D is given by this formula:
Where 
represent the deviation pooled and we know from the problem that:
represent the pooled variance
So then the pooled deviation would be:
And the difference of the two samples is 
, and replacing we got:
And since the value for D obtained is 0.5 we can consider this as a medium effect.
Step-by-step explanation:
Previous concepts
Cohen’s D is a an statistical measure in order to analyze effect size for a given condition compared to other. For example can be used if we can check if one method A has a better effect than another method B in a specific situation.
Solution to the problem
The Cohen's D is given by this formula:
Where represent the deviation pooled and we know from the problem that:
represent the pooled variance
So then the pooled deviation would be:
And the difference of the two samples is , and replacing we got:
And since the value for D obtained is 0.5 we can consider this as a medium effect.
Answer:
the 90th percentile is 145
Step-by-step explanation:
Data provided:
152 121 130 143 122 101 137 98 138 127 145 117
Number of students considered, n = 12
To find:
90th percentile
Now,
Step 1 : Arrange the data in ascending order
98, 101, 117, 121, 122, 127, 130, 137, 138, 143, 145, 152
Step 2 : Compute the position of the 90th percentile
position of the 90th percentile, i = (90% × n)
Thus,
i = 0.90 × 12
or
i = 10.8
Now,
Step 3 : Since, the index i is not an integer, round up to the nearest integer
i.e i = 11
Therefore,
The 90th percentile is the value in 11th position,
i.e 145
First, you have to substitute for x, which would make the problem f(x)=7.45(-4.3)+33.7
Now, you just have to use the PEMDAS method (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
f(x)= -32.035+33.7
f(x)=1.665
