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1 year ago

12

I've done with my quiz, now I have to do the correction for extra point, bit my teacher required to explain how to solve it corr

ectly, but I don't know how. Please help me

1 answer:

lapo4ka [179]1 year ago

7 0

To solve this problem, we have to use the interior angles theorem which states that the sum of all three interior angles of a triangle must sum 180°.

Having said that, we express the following.

$75+x+2x=180$

Now, we solve for <em>x</em>.

$\begin{gathered} 75+3x=180 \\ 3x=180-75 \\ 3x=105 \\ x=\frac{105}{3} \\ x=35 \end{gathered}$

Then, we use this value to find the angle T.

$m\angle T=2x=2(35)=70$ <h2>Therefore, the angle T is equal to 70°.</h2>

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A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk

Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = $1 *10^6$ bytes

kilobyte = $1*10^3$ bytes

and a regular byte would just be $1$

Now, you will need to do a conversion:

$1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}$

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are $1*10^6$ bytes!)

In the second fraction thought, remember one kilobyte is $1*10^3$ bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do $\frac{1kilobyte}{1*10^3bytes}$ , but I think it is more correct to do write it out how I did).

*** They do equal the same thing though! Do whichever way is easier for you!

Now, your answer should be:

$10^3$ kilobytes (1000 kilobytes)

Hope this helped!

6 0

2 years ago

Write 2 1/2 miles in 3/4 hour as a unit rate

ValentinkaMS [17]

Answer:

3 1/3 mph

Step-by-step explanation:

2.5 ÷ 0.75 = 3.3

or

5/2 ÷3/4 = 5/2 · 4/3 = 20/6 or 10/3 = 3 1/3

4 0

3 years ago

What is the area of this triangle? A=bh2 17 m² 30 m² 60 m² 120 m² Right triangle with height labeled 12 m, base labeled 5 m, and

vichka [17]

Answer:

30 m²

Step-by-step explanation:

What is the area of this triangle? A=bh/2 17 m² 30 m² 60 m² 120 m² Right triangle with height labeled 12 m, base labeled 5 m, and third side labeled 13 m.

Area of a triangle = bh/2

b = Base = 5m

h = Height = 12m

Area of the triangle = 5m × 12m/2

= 60m²/2

= 30 m²

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2 years ago

4x − 8y = –20<br> 4x − 7y = –15

Alja [10]

Y = 5
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8 0

2 years ago

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago