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3 years ago

Will give Brainliest for correct answer! :)

Mathematics

2 answers:

Schach [20]3 years ago

6 0

Your best bet is to make a table of the x and y values.

Then plug -2, -1, 0, 1, and 2 in for x, into the equation to get the y values. That's how you get your points.

AfilCa [17]3 years ago

6 0

Step-by-step explanation:

to find y intercept substitute x with 0

and you will get f(0)=3

and to find x intercept make the whole equation equal to zero. x^3+2x^2_3=0

x=1

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Identify the properties used in step 1 and step 2 to solve the equation shown 2x+6=22 then discuss why those properties were use

Jet001 [13]

Answer:

In step 1 subtraction property is used and in step 2 division property is used.

Explanation:

We have the equation 2x + 6 = 22

Step 1

The subtraction property of equality tells us that subtracting the same number to each side of an equation gives us an equivalent equation

So subtracting 6 from both sides

2x + 6 - 6 = 22 - 6

2x = 16

Step 2

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a person invested $6700 for one year, part at 8%, part at 10%, and the remainder at 12%. the total annual income from these inve

lukranit [14]

Answer:

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

Step-by-step explanation:

step 1

Let

x-----> the amount invested at 8% rate

y-----> the amount invested at 10% rate

z-----> the amount invested at 12% rate

$z=(x+y)+300$ ----> equation A

$x+y+z=6,700$ ----> equation B

substitute equation A in equation B

$x+y+(x+y+300)=6,700$

$2x+2y=6,400$

$x+y=3,200$ -----> equation C

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=1\ year\\ P=\$6,700\\ I=\$716$

substitute in the formula above

$716=x(0.08)+y(0.10)+z(0.12)$

substitute equation A

$716=x(0.08)+y(0.10)+(x+y+300)(0.12)$

$716=0.08x+0.10y+0.12x+0.12y+36$

$716=0.20x+0.22y+36$

$0.20x+0.22y=680$ -----> equation D

step 2

Solve the system of equations

x+y=3,200 -----> equation C

$0.20x+0.22y=680$ -----> equation D

Solve the system by graphing

The solution is the point (1,200,2,000)

see the attached figure

Find the value of z

$z=(x+y)+300$

$z=(1,200+2,000)+300=3.500$

therefore

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