301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
A googol is 1.0*10^100. there are <span>25000000000 RBC in the average adult.
The number of adults equals
1.0*10^100 / </span><span>25000000000
=</span>400000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
(=10^100/(25*10^9)=4*10^89)
123.5%
= 123.5/100
= 1235/1000
= (1235/5) / (1000/5)
= 247/200
= 1 47/200
The final answer is 247/200 or 1 47/200~
Answer:
C. 0.99 per day
Step-by-step explanation:
I calculated it logically
60 tables total. 25% of those seat 22 people. 60 X 25% = 15. So 15 of the tables seat 22 people.
The remaining tables (60 tables - 15 tables = 45 tables) seat 44 people.
So you have:
(15 tables X 22 seats) + (45 tables X 44 seats) = total seats.
2310 TOTAL seats.
