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sammy [17]
3 years ago
9

Using induction, verify the inequality. (1 + x)" ? 1 + nx, for x ?-1 and ? 1

Mathematics
1 answer:
klio [65]3 years ago
3 0

Answer with explanation:

The Inequality should be:

   (1+x)^n\geq 1+n x

Where, n and x are any integers.

⇒For, x= -1

L HS

 =[1+(-1)]^n\\\\=(0)^n\\\\=0

R HS

→1+n × (-1)

=1-n

If, n is any Integer, then for, n=1

1-1=0

For, n=2

1-2= -1

....

So,   (1+x)^n\geq 1+n x

for, x=-1.

⇒For, x=1

L HS

 =[1+(1)]^n\\\\=(2)^n

For, n=1

L H S=1

For, =2

L H S=4

R HS

→1+n × (1)

=1+n

If, n is any Integer, then for, n=1

1+1=2

For, n=2

1+2= 3

....

So,    (1+x)^n\geq 1+n x

for, x=1.

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HELP! SIMPLIFY!
Vitek1552 [10]
1)  (m³n⁵)(mn⁴)
     -----------------
      m⁻³n²

Simplify.

m⁴n⁹
-------
m⁻³n²

When the bottom power is a negative, you add it to the power on top, & when the power is a positive, you subtract it.

m⁴ + m³ = m⁷

n⁹ - n² = n⁷

So, our answer for #1 is m⁷n⁷

2)  6a²b³
     ---------
        4a

Please read rules in #1.

6 / 4 = 3/2 & a² - a = a

So, our answer is 3a
                               -----
                                 2

3)  5⁶a⁶b³
     ---------
       5²ab³
5⁶ - 5² = 5⁴ AND a⁶ - a = a⁵ AND b³-b³ = 0

So, our answer is 5⁴a⁵

Simplify 5⁴

5 × 5 × 5 × 5 = 625

So, our final answer is :

625a⁵

~Hope I helped!~
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AfilCa [17]

Answer:

145 yd²

Step-by-step explanation:

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Total area will be the sum of triangular and square faces hence 120+25=145 yd²

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