Answer:
y = 1
Step-by-step explanation:
Passes through (6,-1)(6,-1)
Find the slope (m)
m=(y2 - y1) / (x2 - x1)
m=(-1 - (-1) ) / (6-6)
m= 0
Parallel to x - 3y = 3
-3y = -x +3
y = 1/3 x -1
Equation of the line equation is y - y1 = m ( x - x1 )
y - ( -1 ) = 0 ( x - 6 )
y + 1 = 0
y = 1
The awnser is D to your question
First pic: x=27
second pic: x=15
Happy New Year from MrBillDoesMath!
Answer:
Part A:
point \ coordinates \ quadrant:
I (1,2) 1
L (-4,2) 2
K (-4,0) does not belong to any quadrant
J (3,-1) 4
M (4,-4) 4
Part B:
Point K = (-4,0) lies on the x-axis so reflecting it about the x-axis gives the same point. In other words, the "reflected" point has coordinates (-4,0)
Part C:
L = (-4,2). Reflecting it about the y-axis gives the point (4,2)
Thank you,
MrB
Percy is not correct because he applied the zero product property to a factored expression that was not equal to 0. He should have subtracted 12 from both sides to get x2 + 7x<span> = 0 before factoring. The correct solutions are 0 and -7.</span>
