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Alexus [3.1K]
2 years ago
11

What is the equation of this graphed line?

Mathematics
2 answers:
MrMuchimi2 years ago
6 0
We can find the slow by using the formula y2-y1/x2-x1. We have (-4, -6) and (2, 6). 6+6/2+4 is 12/6 which is 2. We need to put this into point slope form before putting this into slope-intercept form.

I will use the coordinates (2, 6).

y - 6 = 2(x - 2)

This gives us y - 6 = 2x - 4. We need to isolate y. This gives us y = 2x + 2.

I decided to use point slope form because it looks like the y-intercept is 2 and something tenths. However, the line is just off.

The answer is: y = 2x + 2
xz_007 [3.2K]2 years ago
3 0
Answer is highlighted in blue. If you have any questions feel free to ask.
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Its 23.1 one because in 23 minutes they travel three miles

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Given the piece wise function shown below, select all of the statements that are true
allsm [11]
C and d

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8 0
3 years ago
Se golpea (chuta) un balón sobre el piso y sale dando botes parabólicos cada vez menores. Si se lanzo inicialmente con una veloc
Ipatiy [6.2K]

Answer:

a)d = 180,91 m

b)t = 11,76 seg

Step-by-step explanation:

Para el lanzamiento de proyectil, la ecuación que nos da la velocidad en V(y) es:

V(y)  = Voy - g*t

en donde Voy = Vo * senα    ( donde Vo es la velocidad inicial, α el angulo del disparo.

Si en esta ecuación hacemos V(y) = 0 estamos en el punto donde el componente en el eje y de la velocidad del proyectil es cero, ese punto es el punto medio del recorrido.

0 =  Vo*sen 60⁰     - g*t

g*t  =  Vo* √3/2

t  = { 32 [m/s] * √3 }2*9,8 [m/s²]

t = 16*√3  / 9,8

t = 2,8278 seg

El tiempo total del primer recorrido es entonces por simetría

t₁ = 2 * 2,8278           t₁  = 5,6556 seg

La distancia del primer impacto al suelo es:

x = Vox * t₁                        ( Vox es constante   Vx = Vo*cos 60⁰ )

x  =  32 * (1/2) * 5,6556

x₁  =  90,49 m

Aplicando los mismos criterios ahora para el segundo bote

Ahora Vo = 32 -  32*(1/4)

V = 24 m/s

g*t  =  24 * sen 50⁰

t =  24* 0,7660/ 9,8  

t =  1,8759

2*t  = 2*1,8759

t₂  = 3,7518 seg

x₂  =  Vox * t₂

x₂  =  24* 0,6428*3,7518

x₂  =  57,88 m

Y para el tercer bote Vo =  24 - 24(1/4)        Vo = 18 m/s     α = 40⁰

t = 18 *0,6428/9,8

t  = 1,18

2t  = t₃  = 2*1,18

t₃ = 2,36 seg

x₃  = Vox * 2,36                Vox = Vo*cos 40      Vox = 18*0,7660  

Vox = 13,79

x₃  = 13,79*2,36

x₃  = 32,54 m

La distancia total será

d = x₁  + x₂ + x₃

d  =  90,49  + 57,88 + 32,54

d = 180,91 m

y el tiempo total será la suma de los tiempos

t =  t₁  +  t₂  +  t₃

t  = 5,65 + 3,75 + 2,36

t = 11,76 seg

8 0
3 years ago
Need math help please!
loris [4]

Answer:

SAS

Step-by-step explanation:

We can automatically eliminate the HL answer choice, since the given triangles aren't right triangles. The only answer choices that could make sense would be ASA or SAS, but there is no ASA choice, so the answer would be SAS.

5 0
3 years ago
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