If the legs of a right triangle are lengths a and b and the hytponuse is legnth c then
a²+b²=c²
so if the hyptonuse is 20 then
a²+b²=20²
a²+b²=400
hmm, what combos can we do?
find the values of a and b such taht they are whole numbers and a²+b²=400
looking at all the squares from 1 to 20
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
11²=121
12²=144
13²=169
14²=196
15²=225
16²=256
17²=289
18²=324
19²=361
20²=400
which pairs add up to 400?
the only pair is 144+256 which is 12²+16²
the legs are length 12 units and 16 units
Answer:
.8 inches
Step-by-step explanation:
Multiply by the reciprocal of the coefficient of S.
S = 360A/(π·r²)
Any point with coordinates (x, y) reflected across the y-axis is going to have the opposite x value that it did before.
You should be able to find the coordinates yourself for part a. (you didn't provide the original ones so I can't help you there)
Here is the "rule" for a reflection across the y-axis:
![(x,\ y)\rightarrow(-x,\ y)](https://tex.z-dn.net/?f=%28x%2C%5C%20y%29%5Crightarrow%28-x%2C%5C%20y%29)
And when we go 1 unit to the right and 2 down, that's the same as
![(x,\ y)\rightarrow(x+1,\ y-2)](https://tex.z-dn.net/?f=%28x%2C%5C%20y%29%5Crightarrow%28x%2B1%2C%5C%20y-2%29)
Combining those into one rule is pretty simple, Use our result for the first in the second and we would get
![(-x+1,\ y-2)](https://tex.z-dn.net/?f=%28-x%2B1%2C%5C%20y-2%29)
, so the rule is
![\boxed{(x,\ y)\rightarrow(-x+1,\ y-2)](https://tex.z-dn.net/?f=%5Cboxed%7B%28x%2C%5C%20y%29%5Crightarrow%28-x%2B1%2C%5C%20y-2%29)
.
Part A is asking for the coordinates after the reflection (x, y) ⇒ (-x, y).
Part C is asking for the coordinates after the full translation ⇒ (-x+1, y-2)