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3 years ago

The vertex is located at (8.33,236.67). What does this point represent in context

Mathematics

2 answers:

Aneli [31]3 years ago

7 0

Answer:

The vertex is the maximum of the graph.

The maximum daily profit from the sale of soccer balls is $236.67.

The maximum profit occurs when the store charges $8.33 per soccer ball.

Bezzdna [24]3 years ago

6 0

Answer:

It depends on the situation being modeled.

Step-by-step explanation:

Assuming the vertex (8.33,236.67) is on a quadratic curve modeling height of an object in feet after t seconds.

Then t=8.33s is the time the object reached the maximum height.

The maximum height is the y-value of the vertex, which is 236.67 feet.

In this case the quadratic curve opens downwards.

The vertex is then the maximum point on this curve.

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3 years ago

Read 2 more answers

Is the<br> statement (-1)n = -1 true for any positive integer n? Explain.

Rashid [163]

Answer:

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3 years ago

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3 years ago

Which of the following values is a solution of |2-x| less than 4

morpeh [17]

The correct answer is -1.

In order to solve this, we need to split into the positive and negative version of the answers. Let's start with the positive version.

2 - x < 4

-x < 2

x > -2 ----> NOTE: When we divide by -1, we have to change the direction of the sign.

Now we'll do the negative version.

2 - x > -4

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3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: