Answer:
It depends on the situation being modeled.
Step-by-step explanation:
Assuming the vertex (8.33,236.67) is on a quadratic curve modeling height of an object in feet after t seconds.
Then t=8.33s is the time the object reached the maximum height.
The maximum height is the y-value of the vertex, which is 236.67 feet.
In this case the quadratic curve opens downwards.
The vertex is then the maximum point on this curve.