C) p ≤ 78
I got 78 by subtracting 118 by 40. Since we know the maximum is 118 we can't get any higher than 78 so it has to be equal or less than.
Answer:
0.053
Step-by-step explanation:
This is a geometric distribution problem.
I'm geometric distribution problem,
E(X) = 1/p
Where;
E(X) is expected value and p is probability of success
Thus;
1/p = 12.5
p = 1/12.5
p = 0.08
Now, to find the probability that the sixth person tested is the first one with high blood pressure, we will use the probability formula in geometric distribution which is;
P(X = k) = qⁿ•p
q = 1 - p
q = 1 - 0.08
q = 0.92
Thus;probability that the sixth person tested is the first one with high blood pressure will be expressed as;
P(X > 5) = (0.92^(5)) × 0.08
P(X > 5) = 0.053
Answer:
A. {-1, 2, 7}
Step-by-step explanation:
For a set of ordered pairs, the domain is the set of first-numbers (x). The range is the set of second numbers (y, or g(x)).
The first step here is to find the g(x) values for each of the listed x-values.
The attachment shows a table.
Often, we like to list the domain and/or range values in numerical order, eliminating any duplicates. That is, the set of range values {2, -1, -1, 7} would be listed as ...
{-1, 2, 7} . . . . . . matches choice A
_____
You find the g(x) values by substituting for x and doing the arithmetic.
g(-2) = (-2)² -2 = 4 -2 = 2, for example
Answer:
x = 7.07 or 4.925
Step-by-step explanation:
3(x-6)^4+11=15
3(x-6)^4=15-11
(x-6)^4=4/3
x-6 = +![\sqrt[4]{4/3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B4%2F3%7D)
or -
x= + +6 or - +6
x = 7.07 or 4.925
Answer:
100 lightbulbs
Step-by-step explanation:
Basically find the percentage of lightbulbs that are bad. 5/136. So about 3. 6 percent. I'm going to use a more exact form of this percent for my calculations though. Now use the decimal for of this (0.036....) and multiply it by 2720. Using my exact decimal, the answer just so happened to be exactly 100. So there will be 100 defective lightbulbs per day. (Teachers are a stickler for units, so don't forget them if it's for a teacher)
Hope this helps!
