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diamong [38]
3 years ago
6

PLEASE HELPPP

Mathematics
1 answer:
KatRina [158]3 years ago
8 0

Answer:

y x

-1 0

1 1

3 2

5 3

This is a table that follows the above function

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-2(3h-1)=5(2h-3) has how many solutions are there
GREYUIT [131]

Answer:

1 solution

Step-by-step explanation:

-2(3h - 1) =5(2h - 3)

-6h + 2 = 10h - 15

-16h = -17

h = 17/16

Answer: 1 solution

8 0
3 years ago
For what value of x is the function g(x)=x/1-x NOT defined?
VMariaS [17]

The function is definately defined at x=0 but not x=1.

But its just one part of the coordinate (x,y).

If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.

Now I hope you understood what I meant!

Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:

6 0
3 years ago
The letter tiles shown are placed in a bowl. Matt selects one tile from the bowl.
Julli [10]

Answer:

4/10 or 2/5

Step-by-step explanation:

probability of each letter:

J = 0/10

U = 2/10

M = 1/10

P =  1/10

4 0
3 years ago
Suppose we roll a fair six-sided die 20 times and draw ten cards from a standard 52-card deck. Let X be the number of "6"s rolle
Lera25 [3.4K]

Answer:

a) Expected value = 6.406

Variance = 4.905

Standard deviation = 2.45

b) The probability is 0.08547

Step-by-step explanation:

a) Let's suppose that:

X₁ = number of 6´s

X₂ = number of Jack, Queen, King or Aces

The mean of X₁ is:

MeanX₁ = n * p = 20 * (1/6) = 3.33

The variance of X₁ is:

Var-X_{1} =np(1-p)=3.33(1-(1/6))=2.775

The mean of X₂ is:

MeanX₂ = 10 * (16/52) = 3.076

The variance of X₂ is:

Var-X_{2} =3.076(1-(16/52))=2.13

The expect value of X is:

Xexp = MeanX₁ + MeanX₂ = 3.33 + 3.076 = 6.406

The variance of X is:

VarX = VarX₁ + VarX₂ = 2.775 + 2.13 = 4.905

The standard deviation is:

Xdevi = 4.905/2 = 2.45

b) The probability of drawing at least five six out of 20 rolls is equal to:

∑(1/6)ˣ(5/6)²⁰⁻ˣ = 0.231 with x = 5

The probability of at least 4 Jack, Queen, Kings or Aces is:

∑(16/52)ˣ(1-(16/52))¹⁰⁻ˣ = 0.37 with x = 4

The probability of given event is equal to:

P = 0.231 * 0.37 = 0.08547

5 0
3 years ago
Plzzzz I need help. Algebra!!!!!! The length of a rectangle is 2 more than 3 times its width. Find the dimensions of the rectang
defon

Answer:

W = 5 in.

L = 17 in

Step-by-step explanation

L = Length W = Width

L = 2 + 3w

44 = 2L + 2W

44 = 2(2+3W) + 2W

44 = 4 + 6W + 2W

40 = 8W

5 = W

6 0
3 years ago
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