A company introduces a new product for which the number of units sold S is

1 answer:

6 0

(a) The "average value" of a function over an interval [a,b] is defined to be

(1/(b-a)) times the integral of f from the limits x= a to x = b.

Now S = 200(5 - 9/(2+t))

The average value of S during the first year (from t = 0 months to t = 12 months) is then:

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12

This equals 200/12 * (5t -9ln(2+t))

Evaluating this with the limits t= 0 to t = 12 gives:

708.113 units., which is the average value of S(t) during the first year.

(b). We need to find S'(t), and then equate this with the average value.

Now S'(t) = 1800/(t+2)^2

So you're left with solving 1800/(t+2)^2 = 708.113

I'll leave that to you

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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. Two students in t

melomori [17]

Answer:

The system of equation used to find the Total number of flash cards made are $\left \{ {{5x+5} \atop {6x}} \right.$ .

In 5 minutes, each student will have 30 flash cards.

Step-by-step explanation:

Given:

Number of flash cards already made by Tristan = 5

Number of flash card Tristan makes in 1 min = 5

Number of flash card Josh makes in 1 min = 6

We need to find the How long will Josh have same number of flashcards.

Also We need to find how many flashcards will each student have at that point.

Solution:

Let the number of minutes be $'x'$ .

Now we can say that;

Total number of flash cards made by Tristan is equal to Number of flash cards already made by Tristan plus Number of flash card Tristan makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Tristan = $5+5x$