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SashulF [63]
3 years ago
15

Please help me find the unit rate of 1/2/3 1 over 2 over 3

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Answer: It would be 12 miles per hour

Step-by-step explanation:

This fraction is equal to 30 miles divided into 2.5 miles which is equal 12 miles per hour.

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What is the retail price of the original price $60 markup : 15%
Nataly [62]
I think the original price is either $51 or $69
4 0
3 years ago
Read 2 more answers
A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.
Verdich [7]

Answer:

2a - 3b + 4c = 1

Step-by-step explanation:

Given

a^2 + b^2 + c^2 = 2(a - b - c) - 3

Required

Determine 2a - 3b + 4c

a^2 + b^2 + c^2 = 2(a - b - c) - 3

Open bracket

a^2 + b^2 + c^2 = 2a - 2b - 2c - 3

Equate the equation to 0

a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0

Express 3 as 1 + 1 + 1

a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0

Collect like terms

a^2 - 2a + 1 + b^2 + 2b + 1 + c^2  + 2c + 1 = 0

Group each terms

(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

Factorize (starting with the first bracket)

(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b^2 + b+b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)(b + 1)) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c^2  + c+c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c(c  + 1)+1(c + 1)) = 0

((a - 1)^2) + ((b + 1)^2) + ((c  + 1)(c + 1)) = 0

((a - 1)^2) + ((b + 1)^2) + ((c  + 1)^2) = 0

Express 0 as 0 + 0 + 0

(a - 1)^2 + (b + 1)^2 + (c  + 1)^2 = 0 + 0+ 0

By comparison

(a - 1)^2 = 0

(b + 1)^2 = 0

(c  + 1)^2 = 0

Solving for (a - 1)^2 = 0

Take square root of both sides

a - 1 = 0

Add 1 to both sides

a - 1 + 1 = 0 + 1

a = 1

Solving for (b + 1)^2 = 0

Take square root of both sides

b + 1 = 0

Subtract 1 from both sides

b + 1 - 1 = 0 - 1

b = -1

Solving for (c  + 1)^2 = 0

Take square root of both sides

c + 1 = 0

Subtract 1 from both sides

c + 1 - 1 = 0 - 1

c = -1

Substitute the values of a, b and c in 2a - 3b + 4c

2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)

2a - 3b + 4c = 2 +3  -4

2a - 3b + 4c = 1

7 0
3 years ago
A recipe for one full cake calls for one fourth cup of sugarIf three eighths of a cup of sugar is used, how many cakes were made
marin [14]

Answer:

1 1/2 cakes

Step-by-step explanation:

3/8 ÷ 1/4

3/8 * 4/1

12/8

3/2

1 1/2

5 0
2 years ago
2. An expression is shown.
laiz [17]

Adding parentheses in the component 9\div 3 of the expression may bring an output of 48.

<h3>Procedure - Application of hierarchy rules in a arithmetic expression</h3>

In this question we should make use of hierarchy rules represented by the use of parentheses. The parentheses oblige to make operations inside it before making it in the rest of the formula.

Now we decide to add parenthesis in the component 9\div 3 such that the result of the entire expression is 48. We proceed to present the proof:

2 \times 8 \times (9\div 3)

2\times 8 \times 3

2\times 24

48

Adding parentheses in the component 9\div 3 of the expression may bring an output of 48. \blacksquare

<h3>Remarks</h3>

The statement presents mistakes and is poorly formatted. Correct form is shown below:

An expression is shown: 2\times 8 \times 9 \div 3

Using the same expression, add parenthesis so that the value of the expression is 48.

To learn more on hierarchy rule, we kindly invite to check this verified question: brainly.com/question/3572440

5 0
3 years ago
How do you translate "fifty-three plus four times c is as much as 21" in an equation
Ulleksa [173]
53+4c=21 \\ \\ 4c=21-53 \\ \\ 4c=-32 \\ \\ c= -\frac{32}{4} \\ \\ \boxed{c=-8}
4 0
3 years ago
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