Answer:
Step-by-step explanation:
If from 0 - 10 there is 1 number ending in 3 (3) we'll aplly the same logic to 500.
Between 0-10 there is 3. Between 10 - 20 there is 13. Between 20-30 there is 23. Between 30-40 there is 33, etc.
If we divide 500 into 10 we get 50:
500 / 10 = 50
That means there are 50 groups of 10 in the number 500. If we know that every 10 numbers has 1 ending in 3, we multiply 1 by 50:
1 x 50 = 50
So, our conclusion is, that there are 50 numbers ending in 3 between 10 and 500.
Hope it helped,
BioTeacher101
Answer:
D. (2,-3)
Step-by-step explanation:
if you substitute 2 for the x value and -3 for the y value in both equations, it works out.
instead of y=3x-9 it would be -3=3(2)-9.
you solve and get -3=-3, so it's a solution.
and instead of y=-2x+1 it would be -3=2(2)+1. after solving it, you would get -3=-3 again, so it works for both equations.
The height would be 10. 8+8=16 36-16=20 10×2=20 to get perimeter you add up all the sides in this case it's a rectangle so you would multiply 8 by 2 and then 10 by 2 and add
The standard form of ellipse with vertical major axis and center at the origin is:
x^2/b^2+y^2/a^2=1, a>b
2a=length of the major axis=28
a=14
a^2=196
2b=length of minor axis=20
b=10
b^2=100
x^2/196+y^2/100=1
making y the subject we get
y=5/7(196-x²)^0.5