You should multiply the experimental probability by the total number of trials in an actual experiment when making a prediction.
<h3>What is an
experimental probability?</h3>
An experimental probability is also referred to as relative frequency or empirical probability and it can be defined as a ratio of the number of outcomes for the occurrence of a specific event to the total number of trials in an actual experiment.
In order to make a prediction by using experimental probability, you should multiply the experimental probability by the total number of trials in an actual experiment.
Read more on experimental probability here: brainly.com/question/10128393
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We have that
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer <span>
considering the case N 2 </span>
isvertex (4,-1)------> is correcty intercept (0,-17)-----> is correctaxis of symmetry x=4-----> is correct
step by step have no idea but it's a
10 5/12 can be turned into a improper fraction by multiplying 10 and 12. You get 120. Then you can add 5 and get 125/12.
THE ANSWER IS 125/12!
Answer:
Option C is true - The number of students who read 4 books or fewer
Step-by-step explanation:
Here, to find the mean and median, we do not have proper information or specific values. We just have the ranges, so both the mean and median cannot be determined. So, options A and B are not correct.
We can see two bins covering the 9 or more books, so option D cannot be true either.
Therefore, only option C is left and that is true.- the number of students who read 4 books or fewer.