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jenyasd209 [6]
3 years ago
12

Write an equation of the line that passes through the point (-4,-1) and is parallel and perpendicular to the line 2x+7y=14

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer: Parallel: y=-2/7x-2 1/7 Perpendicular: y=7/2x+13

Step-by-step explanation:

2x+7y=14

Subtract 2x from both sides.

7y=-2x+14

Divide both sides by 7 to isolate y.

y=-2/7x+2

Parallel:

Plug in x and y with same slope as the original.

-1=-2/7(-4)+b

Solve for b:

-1=8/7+b

-2 1/7=b

y=-2/7x-2 1/7

Perpendicular:

Plug in x and y with the negative inverse of the original slope.

-1=7/2(-4)+b

Solve for b.

-1=-28/2+b

-1=-14+b

13=b

y=7/2x+13

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2 years ago
Ab=45 mm,bc=10cm 4mm ,cd = 5 cm 6 mm ,de= 35 mm,ea=x cm, and the perimeter of irregular pentagon is 280 mm. Find the length of t
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The length of the unknown side x is 4 cm

Step-by-step explanation:

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AB=45 mm ------> convert to cm -----> AB=45/10=4.5 cm

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