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3 years ago

6

Which of these side lengths makes the triangle obtuse? 15, 36,

1 answer:

gogolik [260]3 years ago

8 0

Answer:

I believe the answer is 36.

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Solve each equation for p.<br> P+3/m=-1

Otrada [13]

Answer:

P= -m-3

I hope this helps!

3 0

3 years ago

Will give brainliest

ehidna [41]

Answer:

25.047 or roughly 25.

Step-by-step explanation:

I solved it wrong the first time then i double check with wolframalpha and got the correct number.

We know that the area of the tile is 18 $\sqrt{3}$ and it makes a triangle, we also know the base and height. In this case the base is 2 $\sqrt{3}^{x/12}$ and the height is also given which is $\sqrt{3}^{\frac{x}{6} }$ .

Area of triangle = $\frac{bh}{2}$ ,

substituting we will end up with 18 $\sqrt{3}$ =( 2 $\sqrt{3}^{x/12}$ * $\sqrt{3}^{\frac{x}{6} }$ ) / 2

Here is the tricky part $\sqrt{x} = x^{\frac{1}{2} }$ , i totally forgot about that lol.

Simplifying: we will get 18 $\sqrt{3}$ = $3^{\frac{x}{8} }$

Now, in order to find the x, we will need to take the log of both sides.

$log18\sqrt{3} = \frac{x}{8} log3$

Solving for x we end up getting:

$8\frac{log18\sqrt{3} }{log3}$ = x

where x = 25.047.

To be honest I deserve a nobel prize not a brainliest lol.

Good question bro, take it easy.

5 0

3 years ago

For what values of theta, °

Anna11 [10]

Answer:

Step-by-step explanation:

6 0

2 years ago

Fine The slope of the line on the graph

Brrunno [24]

Take any 2 points through which the line on graph passes,

(0,-1) =(x₁,y₁)

& (2,-4)=(x₂,y₂)

slope=(y₂-y₁)/(x₂-x₁)

=[-4-(-1)]/(2-0)

=-3/2

3 0

3 years ago

PLEASE HELP ME WITH THESE FOUR QUESTIONS TYSMMM!!! THANK YOU

Dima020 [189]

Answer:

$107^\circ, 133^\circ, 20^\circ, \text{and}, 23^\circ$

Step-by-step explanation:

9. For the lines 'm' and 'n' to be parallel the sum of interior angles should be 180 degrees that is:

$x+73^\circ=180^\circ$

$x=107^\circ$

10. For the lines 'm' and 'n' to be parallel the alternate exterior angles should be equal that is:

$147^\circ=x+14^\circ$

$x=147^\circ-14^\circ$

$x=133^\circ$

11. For the lines 'm' and 'n' to be parallel alternate angles should be equal that is:

$180^\circ-3x=2x+20^\circ$

Solving for 'x' we get:

$180^\circ-20^\circ=3x+2x$

$5x=160^\circ$

$x=32^\circ$

12. For the lines 'm' and 'n' to be parallel corresponding angles should be equal that is:

$(7x-11)^\circ=(4x+58)^\circ$

$7x-4x=58^\circ+11^\circ$

$3x=69^\circ$

$x=\frac{69}{3}=23^\circ$

8 0

3 years ago