Answer:
A
Step-by-step explanation:
We are given:
Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):
So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.
And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.
Cosecant is given by the hypotenuse over the opposite side. Thus:
Since θ is in QIII, cosecant must be negative:
Our answer is A.
Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
Answer link
Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
Answer link
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Answer:
96
Step-by-step explanation:
Its a pattern :) BTW can you help with mine please
<span>To solve it, use the quadratic formula with (½)(-32.174 ft/s²) = a, 38 ft/s = b, and 30 ft = c. There are two answers; the only positive answer is t = 2.986 s </span>
